我想定义一个函数,它可以通过向其添加1([1,1,1,...])来改变输入列表。 但是,我不想使用循环来执行这个简单的操作。
# input - a list (empty list)
# - number of elements to initialize
# output- None
# - But it will have to mutate the inputted (list)
def initialize_one(empty_lis, n):
# Do nothing if e_lis is a non-empty list
if len(empty_lis) is not 0:
return
else:
temp = [1] * n
# empty_lis = temp will not mutate
# And I don't want to use loops to append
# because if n = 100,000
# it will have to loop for 100,000 times
lis = []
n = 10
initialize_one(lis, n)
print lis
# expected output
# >>>[1, 1, 1, 1, 1, 1, 1, 1, 1]
答案 0 :(得分:3)
def initialize_one(seq, n):
if not seq:
seq[:] = [1] * n