Question

我尝试执行我的第一个春季应用程序，但我收到错误。我是春天的新手你可以帮助我在这里，我将不胜感激。这是代码

 package com.bam.springexample;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class MainApp {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        ApplicationContext context = new ClassPathXmlApplicationContext("Beans.xml");
        HelloSpring obj = (HelloSpring)context.getBean("msgid");
        obj.getMessage();
    }

}

这是POJO类......

package com.bam.springexample;

public class HelloSpring {
private String message;

public void getMessage() {
System.out.println("Your Message is "+ message);
}

public void setMessage(String message) {
    this.message = message;
}
}

beans.xml是

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

   <bean id="msgid" class="com.bam.springexmple.HelloSpring">
       <property name="message" value="Hello Bamadeva Its your first Spring Program ."/>
   </bean>

</beans>

我得到的错误是

Jun 16, 2013 10:12:22 AM org.springframework.context.support.AbstractApplicationContext prepareRefresh
INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@1608e05: display name [org.springframework.context.support.ClassPathXmlApplicationContext@1608e05]; startup date [Sun Jun 16 10:12:22 IST 2013]; root of context hierarchy
Jun 16, 2013 10:12:22 AM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
INFO: Loading XML bean definitions from class path resource [Beans.xml]
Exception in thread "main" org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [Beans.xml]; nested exception is java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:320)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:290)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:142)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:158)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:184)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:112)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:79)
    at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:97)
    at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:411)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:338)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:122)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:66)
    at com.bam.springexample.MainApp.main(MainApp.java:13)
Caused by: java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:142)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:307)
    ... 12 more

提前致谢...

将bean.sml放入src文件夹

后编辑

Caused by: org.xml.sax.SAXParseException: The processing instruction target matching "[xX][mM][lL]" is not allowed.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.reportFatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.scanPIData(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanPIData(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.scanPI(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(Unknown Source)
    at org.springframework.beans.factory.xml.DefaultDocumentLoader.loadDocument(DefaultDocumentLoader.java:78)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:361)
    ... 13 more

Answer 1

找不到bean文件Beans.xml。您应该在类路径中放置Beans.xml。

enter image description here

右键单击eclipse中的src文件夹，然后单击new然后other并创建一个新的xml文件。将beans.xml的所有代码放在该文件中。

 <bean id="helloWorld" class="com.practice.HelloWorld">
   <property name="message" value="Hello World!"/>
 </bean>

我将bean声明为如上所述。

按如下方式调用bean。

 ApplicationContext context = 
         new ClassPathXmlApplicationContext("Beans.xml");

  HelloWorld obj = (HelloWorld) context.getBean("helloWorld");

这对我有用。我可以得到消息的价值。

Answer 2

Spring正在寻找Beans.xml而未在类路径上找到。

该文件可能位于您当前的工作目录或人类显而易见的其他位置，但它必须位于ClassPathXmlApplicationContext的Java类路径上才能正确找到它。

Answer 3

转到应用程序的物理位置并放置.xml文件

Ex：C：\ Workspace \ application-name \ target \ classes

Answer 4

将Beans.xml放入项目的构建路径中。以下是步骤

右键单击项目=>选择构建路径 =>选择配置构建路径
选择Java构建路径=>源=>单击包含

然后单击添加并添加您的Beans.xml
最终配置如下：

点击完成并保存所有更改。使用 ctrl + F11 运行项目。

Spring程序没有被执行

4 个答案: