Question

例如，用户输入@John_Smith hi, what's up!? 我想打电话给John_Smith，并通知他让他注意我该如何存档？

username = @comment ??????(I have no idea how to code it here)
@user = User.find_by_username(username)
current_user.send_message(@user, body, subject)

判断方式是@username(one space)

Answer 1

username = @comment.scan(/(?<=^@)\w+(?=[\s|~])/).first

控制台测试：

2.0.0-p195 :001 > s = "@John_Smith~hi"
 => "@John_Smith~hi"
2.0.0-p195 :002 > s.scan(/(?<=^@)\w+(?=[\s|_])/).first
 => "John_Smith"

编辑：现在接受~或空格作为分隔符。

Answer 2

匹配字符串中的任何位置：

s.scan(/\@(\w+)/).flatten.first

样品：

>> s
"Hello @Jhon!"

>> s.scan(/\@(\w+)/).flatten.first
"Jhon"

>> s = "@John_Smith hi, what's up!?"
"@John_Smith hi, what's up!?"

>> s.scan(/\@(\w+)/).flatten.first
"John_Smith"

您可能希望http://www.rubular.com了解有关ruby正则表达式的更多信息

如何使用正则表达式获取用户？

2 个答案: