我正在尝试学习python,同时也为自己节省了大量的工作。
我有一个xml文件和一个字典文件映射旧设备ID。
我正在尝试迭代树和任何与字典键匹配的logical_devid子项或者每个字典键找到相应的logical_devid。在任何一种情况下,用它的新值替换logical_devid.text。
e.g。 xml片段
<lun>
<pseudo_dev>emcpower146a</pseudo_dev>
<udev>0x12b00000490</udev>
<product_id>symmetrix</product_id>
<frame_id>000192604705</frame_id>
<logical_devid_type>symm_id</logical_devid_type>
<logical_devid>0A43</logical_devid>
</lun>
的文本文件
0A40 0127
0A41 0128
0A42 0129
0A43 012A
我已将xml文件作为ElementTree对象加载,并将文本文件加载到字典中。
import xml.etree.cElementTree as ET
tree = ET.ElementTree(file='emcpower.mappings')
d = {}
with open("translate-table.txt") as f:
for line in f:
(old, new) = line.split()
d[(old)] = new
我一直试图找出迭代和替换elem.text的最佳方法 我认为最好的方法是迭代字典中的已知更改。
for old_devid, new_devid in d.iteritems():
然后为与logical_devid匹配的子逻辑_devid执行某种xml查找,将elem.text设置为new_devid
这是完整的脚本,几乎可以满足我的需求:
#!的/ usr / bin中/ Python的
try:
import xml.etree.cElementTree as ET
except ImportError:
import xml.etree.ElementTree as ET
#read in emcpower.mappings file as an entire xml tree of elements
tree = ET.ElementTree(file='emcpower.mappings')
# this defines a dictionary with the contents of the translate table which
# is simply the old device ID as key and new device id as value
d = {}
with open("translate-table.txt") as f:
for line in f:
(old, new) = line.split()
d[(old)] = new
for elem in tree.iterfind('lun/logical_devid'):
old_devid = elem.text
new_devid = d.get(old_devid)
try:
new_devid
except NameError:
new_devid = None
else:
if new_devid:
elem.text = new_devid
print "The logical_devid will be changed to", elem.text
tree.write('emcpower.mappings.new', )
答案 0 :(得分:0)
我认为迭代tree
并查看每个logical_devid
是否在d
更有意义。在变量(例如logical_devid
)中有old_devid
后,则:
new_devid = d.get(old_devid)
将查看您是否有替代品。如果new_devid is null
那么它不在字典中。否则,new_devid
应替换树中logical_devid
的当前值。