Question

尝试使用boost::serialization序列化派生类时，boost/archive/detail/oserializer.hpp中的断言（Boost 1.53.0中的第436行）会被触发：

const basic_pointer_oserializer * bpos
    = static_cast<const basic_pointer_oserializer *>(
        boost::serialization::singleton<
            archive_serializer_map<Archive>
        >::get_const_instance().find(*true_type)
    );
BOOST_ASSERT(NULL != bpos);

这是我的MWE：

#include <iostream>
#include <fstream>

#include <boost/archive/polymorphic_xml_oarchive.hpp>

#include <boost/serialization/nvp.hpp>
#include <boost/serialization/access.hpp>
#include <boost/serialization/base_object.hpp>

class base
{
    friend class boost::serialization::access;

    template <class Archive>
    void serialize(Archive &ar, const unsigned int version)
    {
        ar & boost::serialization::make_nvp("test", test);
    }

    int test;

public:
    virtual void print() { std::cout << 1 << std::endl; }
};

class derived : public base
{
    friend class boost::serialization::access;

    template <class Archive>
    void serialize(Archive &ar, const unsigned int version)
    {
        ar & boost::serialization::make_nvp("base", boost::serialization::base_object<base>(*this));
        ar & boost::serialization::make_nvp("test2", test2);
    }

    int test2;

public:
    void print() { std::cout << 2 << std::endl; }
};

int main (int argc, char const *argv[])
{
    base *b = new derived();

    std::ofstream stream("out.xml");
    boost::archive::polymorphic_xml_oarchive ar(stream);
    ar.register_type<derived>();
    ar << boost::serialization::make_nvp("b", b);

    return 0;
}

我也尝试使用BOOST_CLASS_EXPORT_GUID代替register_type，但这也行不通。知道我做错了吗？

Answer 1

您可能并不想使用polymorphic_xml_archive (see docs)。

值得注意的是，多态存档与存档的界面有关，与您要序列化的实体无关（它们总是可以是多态的）。

如果您使用xml_archive，问题就会消失。

派生类行程的序列化提升断言

1 个答案: