根据其他人的评论,这篇文章已被分成几个 来自此smaller questions
的上一版本的OP.在下图中,你能帮我(Newbie to R)
下图是使用pdf设备中的data制作的,布局如下。
m <- matrix(c(1,2,3,3,4,5),nrow = 3,ncol = 2,byrow = TRUE)
layout(mat = m,heights = c(0.47,0.06,0.47))
par(mar=c(4,4.2,3,4.2))
#Codes for Fig A and B
...
#Margin for legend
par(mar = c(0.2,0.2,0.1,0.1))
# Code for legend
...
#Codes for Fig C and D
...
答案 0 :(得分:2)
使用doubleYScale
中的latticeExtra
和长格式的数据(请参阅我的previous answer),您可以简化工作:
我们的想法是创建2个分隔对象,然后使用doubleYScale
合并它们。后者将创建第二个轴。我希望我得到你的ploygon想法,因为不清楚为什么你在OP中反转它。
library(latticeExtra)
obj1 <- xyplot(Variable~TimeVariable|Type,type='l',
groups=time, scales=list(x=list(relation='free'),
y=list(relation='free')),
auto.key=list(columns = 3,lines = TRUE,points=FALSE) ,
data = subset(dat.l,time !=1))
obj2 <- xyplot(Variable~TimeVariable|Type,
data = subset(dat.l,time ==1),type='l',
scales=list(x=list(alternating=2),
auto.key=list(columns = 3,lines = TRUE,points=FALSE),
y=list(relation='free')),
panel=function(x,y,...){
panel.xyplot(x,y,...)
panel.polygon(x,y,col='violetred4',border=NA,alpha=0.3)
})
doubleYScale(obj1, obj2, add.axis = TRUE,style1 = 0, style2 = 1)
答案 1 :(得分:1)
尝试以下方法:
1)对于图例部分
数据可在https://www.dropbox.com/s/4kgq8tyvuvq22ym/stackfig1_2.csv
上找到我使用的代码如下:
data <- read.csv("stackfig1_2.csv")
library(Hmisc)
label1=c(0,100,200,300)
plot(data$TimeVariable2C,data$Variable2C,axes=FALSE,ylab="",xlab="",xlim=c(0,24),
ylim=c(0,2.4),xaxs="i",yaxs="i",pch=19)
lines(data$TimeVariable3C,data$Variable3C)
axis(2,tick=T,at=seq(0.0,2.4,by=0.6),label= seq(0.0,2.4,by=0.6))
axis(1,tick=T,at=seq(0,24,by=6),label=seq(0,24,by=6))
mtext("(C)",side=1,outer=F,line=-10,adj=0.8)
minor.tick(nx=5,ny=5)
par(new=TRUE)
plot(data$TimeVariable1C,data$Variable1C,axes=FALSE,xlab="",ylab="",type="l",
ylim=c(800,0),xaxs="i",yaxs="i")
axis(3,xlim=c(0,24),tick=TRUE,at= seq(0,24,by=6),label=seq(0,24,by=6),col.axis="violetred4",col="violetred4")
axis(4,tick=TRUE,at= label1,label=label1,col.axis="violetred4",col="violetred4")
polygon(data$TimeVariable1C,data$Variable1C,col='violetred4',border=NA)
legend("top", legend = c("Variable A","Variable B","Variable C"), col = c("black","violetred4","black"),
ncol = 2, lwd =c("","",2),pch=c(19,15,NA),cex=1)
输出如下:
2)要使字体大小相同,请使用参数cex
并使其在任何地方都相同。