Question

我需要获取满足条件timediff(delta_ts,creation_ts) > "00:01:00"

的bug_id

我用这个

创建了查询

GROUP_CONCAT(
DISTINCT 
bug_id 
from bugs 
where 
timediff(delta_ts,creation_ts) > "00:01:00" 
SEPARATOR ' '
)

请帮忙，因为我在此查询中收到错误：

select sum(IF(priority="P3",1,0)) P3count,
SUM(IF(priority="P2",1,0)) P2count,
sum(IF(timediff(delta_ts,creation_ts) > "00:01:00",1,0)) exeeded,
GROUP_CONCAT(DISTINCT bug_id from bugs where priority="P2") 
from bugs 
where  bugs.product_id=237 
and bugs.resolution='FIXED' 
and bugs.creation_ts >='2013-06-14 09:00:00' 
and bugs.creation_ts <= '2013-06-16 08:59:59' 
and bug_status="RESOLVED";

投掷错误：

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to usenear 'from bugs where priority="P2") from bugs where bugs.product_id=237 and bugs.res' at line 1

Answer 1

选择总和（IF（优先级=＆＃34; P3＆＃34;，1,0））P3count，SUM（IF（优先级=＆＃34; P2＆＃34;，1,0））P2count，sum（ IF（timediff（delta_ts，creation_ts）＆gt;＆＃34; 00：01：00＆＃34;，1,0））exeeded，（从优先级为＆＃34; P2＆＃34;的错误中选择GROUP_CONCAT（DISTINCT bug_id））作为bugs.product_id = 237和bugs.resolution =＆＃39; FIXED＆＃39;和bugs.creation_ts＆gt; =＆＃39; 2013-06-14 09：00：00＆＃39;和bugs.creation_ts＆lt; =＆＃39; 2013-06-16 08：59：59＆＃39;和bug_status =＆＃34;已解决＆＃34;;

Answer 2

我得到了答案，但查询非常复杂。我在嵌套查询的内部和外部编写相同的条件。

select
sum(IF(priority="P3",1,0)) P3count, 
SUM(IF(priority="P2",1,0)) P2count, 
sum(IF(timediff(delta_ts,creation_ts) > "00:01:00",1,0)) exeeded, 
(select GROUP_CONCAT(DISTINCT bug_id) from bugs 
  where timediff(delta_ts,creation_ts) > "00:01:00" 
  and bugs.product_id=237 
  and bugs.resolution='FIXED' 
  and bugs.creation_ts >='2013-06-14 09:00:00' 
  and bugs.creation_ts <= '2013-06-16 08:59:59' 
  and bug_status="RESOLVED") as exeededbugids 
 from bugs 
 where bugs.product_id=237  
 and bugs.resolution='FIXED' 
 and bugs.creation_ts >='2013-06-14 09:00:00'  
 and bugs.creation_ts <= '2013-06-16 08:59:59'  
 and bug_status="RESOLVED";

+---------+---------+---------+-----------------+
| P3count | P2count | exeeded | exeededbugids   |
+---------+---------+---------+-----------------+
|       5 |       6 |       2 | 3743304,3743305 |
+---------+---------+---------+-----------------+
1 row in set (0.00 sec)

Answer 3

select
 sum(IF(priority="P3",1,0)) P3count, 
 SUM(IF(priority="P2",1,0)) P2count, 
 sum(IF(timediff(delta_ts,creation_ts) > "00:01:00",1,0)) exeeded,
 GROUP_CONCAT(DISTINCT bug_id) as exeededbugids 
from bugs 
 where timediff(delta_ts,creation_ts) > "00:01:00"
 and bugs.product_id=237  
 and bugs.resolution='FIXED' 
 and bugs.creation_ts >='2013-06-14 09:00:00'  
 and bugs.creation_ts <= '2013-06-16 08:59:59'  
 and bug_status="RESOLVED";

mysql group_concat和一个条件

3 个答案: