Question

我正在努力为文件选择制作包含 easygui 的单词计数器程序。我目前使用带有PyDev插件的Eclipse SDK（如果有更好的Python环境的建议）。

以下是我当前状态的代码：

#This program is supposed to take a word file, and count the amount of lines and
#words. If the entered file is not a .txt, .doc, or .docx, then the program will
#ask for a different file.

from easygui import fileopenbox

filename = fileopenbox()
lines, words = 0, 0

#This method will count the amount of lines and words in a program and display
#it to the user
def word_count():
    if filename.endswith('.docx'): #If the file extension is .docx
        print("Your file has" + num_words + "words") #Print the amount of lines and words in the file.
    elif filename.endswith('.doc'): #If the file extension is .doc
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.txt'): #If the file extension is .txt
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.py'): #If the file extension is .py
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    elif filename.endswith('.java'): #If the file extension is .java
        #<CODE WHICH COUNTS LINES AND WORDS>
        print("Your file has", lines, "lines, and" ,"words") #Print the amount of lines and words in the file.
    else:
        print("Are you trying to annoy me? How about giving me a TEXT or SOURCE CODE file, genius?")#Print an insulting error message.

如代码所示，我希望程序读取文件扩展名，如果匹配其中任何一个，请运行单词count代码。但是，我的问题是，那个字数代码是什么？似乎使用easygui中的fileopenbox（）会使事情变得更加复杂。感谢提前感谢任何帮助

Answer 1

from easygui import fileopenbox

def word_count(filename):
    if not filename.endswith(('.txt', '.py', '.java')):
        print('Are you trying to annoy me? How about giving me a TEXT or SOURCE CODE file, genius?')
        return

    with open(filename) as f:
        n_lines = 0
        n_words = 0
        for line in f:
            n_lines += 1
            n_words += len(line.split())
    print('Your file has {} lines, and {} words'.format(n_lines, n_words))

filename = fileopenbox()
word_count(filename)

Python EasyGUI字数统计

1 个答案: