我有这个mysql查询，它给我ID = 5时的所有子元素，现在我想按ID对结果进行分组，并计算每个级别有多少元素= 5
`SELECT t1.ID, t1.name,
t1.ID as level1, t1.introID as i1,
t2.ID as level2, t2.introID as i2,
t3.ID as level3, t3.introID as i3,
t4.ID as level4, t4.introID as i4,
t5.ID as level5, t5.introID as i5,
t6.ID as level6, t6.introID as i6,
t7.ID as level7, t7.introID as i7,
t8.ID as level8, t8.introID as i8,
t9.ID as level9, t9.introID as i9,
t10.ID as level10, t10.introID as i10
FROM members AS t1
LEFT JOIN members AS t2 ON t2.parentID = t1.ID
LEFT JOIN members AS t3 ON t3.parentID = t2.ID
LEFT JOIN members AS t4 ON t4.parentID = t3.ID
LEFT JOIN members AS t5 ON t5.parentID = t4.ID
LEFT JOIN members AS t6 ON t6.parentID = t5.ID
LEFT JOIN members AS t7 ON t7.parentID = t6.ID
LEFT JOIN members AS t8 ON t8.parentID = t7.ID
LEFT JOIN members AS t9 ON t9.parentID = t8.ID
LEFT JOIN members AS t10 ON t10.parentID = t9.ID
LEFT JOIN members AS t11 ON t11.parentID = t10.ID
WHERE t1.ID = 5
group by t2.id, t3.id, t4.id, t5.id, t6.id, t7.id, t8.id, t9.id, t10.id`
这会产生这样的结果：
ID NAME LEVEL1 I1 LEVEL2 I2 LEVEL3 I3 LEVEL4 I4
5 Vina Malik 5 0 14 0 41 0 122 0
5 Vina Malik 5 0 14 0 41 0 123 0
5 Vina Malik 5 0 14 0 41 0 124 0
5 Vina Malik 5 0 14 0 42 0 125 0
5 Vina Malik 5 0 14 0 42 0 126 0
5 Vina Malik 5 0 14 0 42 0 127 0
5 Vina Malik 5 0 14 0 43 0 128 5
5 Vina Malik 5 0 14 0 43 0 129 0
5 Vina Malik 5 0 14 0 43 0 130 0
5 Vina Malik 5 0 15 0 44 0 131 0
5 Vina Malik 5 0 15 0 44 0 132 0
5 Vina Malik 5 0 15 0 44 0 133 0
5 Vina Malik 5 0 15 0 45 5 134 0
5 Vina Malik 5 0 15 0 45 5 135 0
5 Vina Malik 5 0 15 0 45 5 136 5
5 Vina Malik 5 0 15 0 46 0 137 0
5 Vina Malik 5 0 15 0 46 0 138 0
5 Vina Malik 5 0 15 0 46 0 139 0
5 Vina Malik 5 0 16 0 47 0 140 0
5 Vina Malik 5 0 16 0 47 0 141 0
5 Vina Malik 5 0 16 0 47 0 142 0
5 Vina Malik 5 0 16 0 48 0 143 5
5 Vina Malik 5 0 16 0 48 0 144 0
5 Vina Malik 5 0 16 0 48 0 145 0
5 Vina Malik 5 0 16 0 49 5 146 0
5 Vina Malik 5 0 16 0 49 5 147 0
5 Vina Malik 5 0 16 0 49 5 148 0
我想在每个i列中得到elemtents的数量等于5，并将每个id的结果分组，然后从select中删除ID，计算每个i列中有多少个元素= 5的最终条件是这个，在i1和i2中没有元素，但在i3和i4中，我们可以在LEVEL3列中看到具有introID = 5的子元素的ID，在这种情况下，我们可以看到重复元素45和49，其中i4 = 5的值，但是当计算它时，当实际情况是第I3列必须为2时，可能会得到6
ID NAME LEVEL1 I1 LEVEL2 I2 LEVEL3 I3 LEVEL4 I4
5 Vina Malik 5 0 14 0 43 0 128 5
5 Vina Malik 5 0 15 0 45 5
5 Vina Malik 5 0 15 0 45 5
5 Vina Malik 5 0 15 0 45 5 136 5
5 Vina Malik 5 0 16 0 48 0 143 5
5 Vina Malik 5 0 16 0 48 0
5 Vina Malik 5 0 16 0 48 0
5 Vina Malik 5 0 16 0 49 5
5 Vina Malik 5 0 16 0 49 5
5 Vina Malik 5 0 16 0 49 5
所以最后的结果必须是这样的：
ID NAME I1 I2 I3 I4
5 Vina Malik 0 0 2 3
任何人都可以帮我分组并计算所有内容以获得所需的结果吗？ 感谢
答案 0 :(得分：1)
我将回应上面的评论，您应该考虑重新设计数据库架构。
但是 - 根据您拥有的架构，我相信此查询可以满足您的需求：
SELECT t1.ID, t1.name,
COUNT(distinct IF(t1.introID = 5, t1.ID, NULL)) AS I1,
COUNT(distinct IF(t2.introID = 5, t2.ID, NULL)) AS I2,
COUNT(distinct IF(t3.introID = 5, t3.ID, NULL)) AS I3,
COUNT(distinct IF(t4.introID = 5, t4.ID, NULL)) AS I4,
COUNT(distinct IF(t5.introID = 5, t5.ID, NULL)) AS I5,
COUNT(distinct IF(t6.introID = 5, t6.ID, NULL)) AS I6,
COUNT(distinct IF(t7.introID = 5, t7.ID, NULL)) AS I7,
COUNT(distinct IF(t8.introID = 5, t8.ID, NULL)) AS I8,
COUNT(distinct IF(t9.introID = 5, t9.ID, NULL)) AS I9,
COUNT(distinct IF(t10.introID = 5, t10.ID, NULL)) AS I10
FROM members AS t1
LEFT JOIN members AS t2 ON t2.parentID = t1.ID
LEFT JOIN members AS t3 ON t3.parentID = t2.ID
LEFT JOIN members AS t4 ON t4.parentID = t3.ID
LEFT JOIN members AS t5 ON t5.parentID = t4.ID
LEFT JOIN members AS t6 ON t6.parentID = t5.ID
LEFT JOIN members AS t7 ON t7.parentID = t6.ID
LEFT JOIN members AS t8 ON t8.parentID = t7.ID
LEFT JOIN members AS t9 ON t9.parentID = t8.ID
LEFT JOIN members AS t10 ON t10.parentID = t9.ID
LEFT JOIN members AS t11 ON t11.parentID = t10.ID
WHERE t1.ID = 5
group by t1.id;
您可以在此处查看SQLFiddle：http://sqlfiddle.com/#!2/3e109/5