many_to_many,sti和将分页

时间:2009-11-10 23:14:22

标签: ruby-on-rails ruby single-table-inheritance will-paginate

我有以下代码

class Category < ActiveRecord::Base
  has_many :categorizations
  has_many :posts, :through => :categorizations
end

class Post < ActiveRecord::Base
  has_many :categorizations
  has_many :categories, :through => :categorizations
end

class Categorization < ActiveRecord::Base
  belongs_to :post
  belongs_to :category
end

class NewsArticle < Post
end
好的,看起来不错。我试图从类别

获取所有NewsArticle
@news_articles = NewsArticle.paginate_by_category_id params[:category],
  :page => params[:page], :per_page => 10,
  :order => 'posts.created_at DESC'

我看到了

 NoMethodError in News articlesController#category

undefined method `find_all_by_category' for #<Class:0x103cb05d0>

我该怎么做才能解决这个问题?

2 个答案:

答案 0 :(得分:2)

怎么样:

@news_articles = NewsArticle.paginate(:conditions => { :category_id => params[:category_id].to_i }, :page => params[:page], :per_page => 10, :order => 'posts.created_at DESC')

您是否将类别ID传递为params[:category]params[:category_id]?如果您不确定可以在视图中debug(params)

答案 1 :(得分:1)

我会添加命名范围并将其与paginate一起使用:

class Post < ActiveRecord::Base
  ..
  named_scope :newest, :order => 'posts.created_at DESC'
  named_scope :by_category, lambda { |category_id| { 
    :joins => :categories,
    :conditions => ['categories.category_id = ?', category_id]
  } }
end

@news_articles = NewsArticle.newest.by_category(params[:category]).paginate(
  :page => params[:page], :per_page => 10
  )