Question

有没有办法使用CodeIgniter中的表单助手创建MySQL链接下拉菜单？我试图这样做，但我似乎无法让它工作。

模型

function get_airports()
    {
        $this->db->select('airport_code, airport_name');
        $this->db->order_by('airport_code', "asc");
        $query = $this->db->get('airports');
    foreach ($query->result_array() as $row){
        $data{$row['airport_code']} = $row['status'];
    }

    }return $data;
    }
    function create_member()
    {
        $new_member_insert_data = array('first_name' => $this->input->post('first_name'),
            'last_name' => $this->input->post('last_name'), 
            'email_address'=> $this->input->post('email_address'),
            'username'=> $this->input->post('username'),
            'password'=> md5($this->input->post('password'))
            'birthdate'=> $this->input->post('birthdate'),
            'base'=> $this->input->post('base')
        );
        $insert = $this->db->insert('membership', $new_member_insert_data);
        return $insert;
    }

} ?>

查看

echo form_dropdown('base', set_value('base', 'Select a Base'));

控制器

$this->form_validation->set_rules('base', 'Base', 'trim|required');

Answer 1

一种方法是让你的下拉列表如下：

<?PHP 
                $options    =   $this->db->query('Select province_id as value, province as display FROM ndi_provinces')->result();
                $prov_options = array(''=>'Select');
                foreach($options as $option){
                    $prov_options[$option->value] = $option->display;
                }
                $prov_optionAtt = "id='province_id'  readonly='readonly'";
                echo form_dropdown('province_id',$prov_options, isset($_POST['province_id'])?$_POST['province_id']:$participant->province_id, $prov_optionAtt);
            ?><span class="required">*</span>

另一种更好的方法是在控制器中创建下拉选项并将其作为变量发送到视图

表单助手下拉菜单

1 个答案: