所以我正在为我们的服务器制作一个库存脚本，并在存储上遇到了障碍。这是代码：
$StorageInfo=Get-WmiObject win32_volume | Where-Object {$_.DriveType -eq 3 -and $_.Label -ne 'System Reserved' -and $_.DriveLetter -ne $null}
$DriveLetters=$StorageInfo | Select-Object DriveLetter | Sort-Object DriveLetter | ft -HideTableHeaders
$DriveNames=$StorageInfo | Sort-Object DriveLetter | Select-Object Label | ft -HideTableHeaders
$DriveCapacity=$StorageInfo |Sort-Object DriveLetter | ForEach-Object {[Math]::Truncate($_.Capacity / 1GB)}
$DriveLetters
$DriveNames
$DriveCapacity
来自的数据如下：
C:
D:
E:
F:
G:
OSDisk
Data
SQL Data
SQL Logs
SQL Temp
232
97
97
97
48
我希望能够将其格式化为：
C:\, OSDisk - 232gb
D:\, Data - 97gb
C:\, SQLData - 97gb
C:\, SQLLogs - 97gb
C:\, SQLTemp - 97gb
......我无法理解这一点。有人可以提供帮助吗？
答案 0 :(得分：2)
尝试这种方式：
Get-WmiObject win32_volume -Filter "DriveType=3 AND Label <> 'System Reserved' AND DriveLetter IS NOT NULL" |
Select-Object Name,Label,@{Name='CapacityGB';E={[Math]::Truncate($_.Capacity / 1GB)}}
如果您想要所描述的确切输出（感谢Ansgar）：
Get-WmiObject win32_volume -Filter "DriveType=3 AND Label <> 'System Reserved' AND DriveLetter IS NOT NULL" | ForEach-Object{
"{0}, {1} - {2}gb" -f $_.Name,$_.Label,([Math]::Truncate($_.Capacity/1GB))
}
答案 1 :(得分：0)
$logfile = <log file path>
$path = <path of the file to which we need to sort>
$Array = gc $path
$Count = $Array.Count
for($i=0; $i -le $Count; $i++)
{ $a =$Array[$i]
$i = $i+1
write-output $i | out-file $logfile
$a+=" "+ $Array[$i]
$i = $i+1
write-output $i | out-file $logfile
$a+=" "+ $Array[$i]
write-output $i | out-file $logfile
$New = $a | Select-Object -Unique #| out-file $logfile }