Question

我正在尝试做类似的事情：

select fred.name
  , fred.emp_num
from fred
  , joe
  , (select * from
      (select yr_bonus
        , 1 grade
      from mark 
      where mark.department = fred.department)
      union
      (select
        0 yr_bonus
        , 2 grade
      from dual)
    ) pay
where fred.division = joe.division
and fred.grade = pay.grade;

这不起作用。我似乎无法弄清楚如何将mark.department绑定到fred.department，从2级深处选择。我该如何做到这一点？

Answer 1

因为在FROM子句中您无法访问另一个表，所以必须在where子句中使用JOINS或连接表。此外，您的查询似乎不正确，描述您想要做什么？

如果我理解正确，您的查询可以像这样重写：

select fred.name
  , fred.emp_num
from fred
  , joe
where fred.division = joe.division
and ((fred.grade = 1 and fred.department in (select department from mark) 
or (fred.grade = 2))

Answer 2

SELECT  fred.name
,       fred.emp_num
FROM    fred
JOIN    joe
ON      fred.division = joe.division
JOIN
(
        SELECT  *
        FROM
        (
            SELECT  yr_bonus
            ,       1 grade
            FROM    mark
            UNION
            SELECT  0 yr_bonus
            ,       2 grade
            FROM    dual
        ) mark
        JOIN    fred
        ON      mark.department = fred.department
) pay
ON      fred.grade = pay.grade;

SQL（Oracle）嵌套的选择参数

2 个答案: