Question

我有以下代码来显示mysql数据库中的六个产品块。它显示为两列三行，我在六个位置中的每一个都获得单独的照片和正确的页面链接，但第一列中的三个产品的alt标签在第2列中重复。我无法弄清楚原因。有什么想法，以及改进代码的方法吗？

<?php
  // create query
  $query = "SELECT * FROM photogear WHERE qty != 0 ORDER BY id DESC LIMIT 6";
  // execute query
  $result = mysql_query($query) or die(MYSQL_ERROR);
?>
  <table>
    <?php 
    while($row = mysql_fetch_array($result)){
      $product2=$row['product'];
      $img2=$row['img'];
      $manuid2=$row['manuid'];
      $id2=$row['id'];
      $price=$row['price'];
    //GET MANUFACTURER FOR DISPLAY IN img title
      $manu_q = "SELECT * FROM manufacturers WHERE manuid = '$manuid2' ORDER BY name";
      $manu_r = mysql_query($manu_q) or die(mysql_error());
      $manu_info = mysql_fetch_array($manu_r);
      $name2=$manu_info['name'];
    ?> 
      <tr>
        <td>
          <?php // for each product show photo with a link to product page 
          echo "<a href='product-".$row['id']."'><img src='".$row['img']."'alt='$name2,$product2 $price' title='$name2 $product2 &pound;$price' width='85'></a>";
         ?>
         <?php $row=mysql_fetch_assoc($result); // make one record out.?>
       </td>  
       <td> 
         <?php // for each product show photo with a link to product page 
echo "<a href='product-".$row['id']."'><img src='".$row['img']."' alt='$name2, $product2 $price' title='$name2 $product2 &pound;$price' width='85'></a>";?>
      </td>
    </tr>
       <?php
} // End loops.
?>
</table>

任何帮助非常感谢

Answer 1

而不是使用$ product2，$ price尝试使用$ row ['product']，$ row ['price']在alt

Answer 2

试试这个，但我不确定使用此

     SELECT * FROM manufacturers WHERE manuid = '$row['manuid']' ORDER BY name

而不是这个

     SELECT * FROM manufacturers WHERE manuid = '$manuid2' ORDER BY name

在此之后

     $row=mysql_fetch_assoc($result);

     Add this line
          $manu_info = mysql_fetch_assoc($manu_r);

防止动态PHP表正确显示

2 个答案: