我已经尝试了很多来解决这个小问题......我正在尝试更新PHPmyadmin数据库中的记录。
$query = 'UPDATE movie SET
movie_name = "'.$_POST['movie_name'].'";
movie_year = '.$_POST['movie_year'].';
movie_type = "'.$_POST['movie_type'].'";
movie_leadactor = "'.$_POST['movie_leadactor'].'";
movie_director = "'.$_POST['movie_director'].'";
movie_running_time = "'.$_POST['movie_time'].'";
movie_cost = "'.$_POST['movie_cost'].'";
movie_takings = "'.$_POST['movie_earn'].'"';
但是当我在sql中放入此查询时,它显示错误。
这是我的简单查询.....
UPDATE movie SET movie_name = "XXX"; movie_year = 2010; movie_type = "7"; movie_leadactor = "4"; movie_director = "6"; movie_running_time = "90 "; movie_cost = "6.0 "; movie_takings = "22.0 "
我该如何解决?请帮忙
错误发生在movie_year上。错误代码是1064
答案 0 :(得分:3)
为什么你使用'; '而不是','分隔符....用逗号分隔符','修改如下
$query = 'UPDATE movie SET
movie_name = "'.$_POST['movie_name'].'",
movie_year = '.$_POST['movie_year'].',
movie_type = "'.$_POST['movie_type'].'",
movie_leadactor = "'.$_POST['movie_leadactor'].'",
movie_director = "'.$_POST['movie_director'].'",
movie_running_time = "'.$_POST['movie_time'].'",
movie_cost = "'.$_POST['movie_cost'].'",
movie_takings = "'.$_POST['movie_earn'].'"';
并尝试使用' mysql_real_escape_string '来逃避帖子值
答案 1 :(得分:3)
在每行末尾使用,
代替;
UPDATE movie
SET movie_name = "XXX",
movie_year = 2010,
...
答案 2 :(得分:1)
你错过了逗号部分
$query = 'UPDATE movie SET
movie_name = "'.$_POST['movie_name'].',";
movie_year = '.$_POST['movie_year'].',;
movie_type = "'.$_POST['movie_type'].',";
movie_leadactor = "'.$_POST['movie_leadactor'].',";
movie_director = "'.$_POST['movie_director'].',";
movie_running_time = "'.$_POST['movie_time'].',";
movie_cost = "'.$_POST['movie_cost'].',";
movie_takings = "'.$_POST['movie_earn'].'"';
答案 3 :(得分:0)
试试这个:
$movie_name=$_POST['movie_name'];
$movie_year=$_POST['movie_year'];
$movie_type=$_POST['movie_type'];
$movie_leadactor=$_POST['movie_leadactor'];
$movie_director=$_POST['movie_director'];
$movie_time=$_POST['movie_time'];
$movie_cost=$_POST['movie_cost'];
$movie_earn=$_POST['movie_earn'];
$query = "UPDATE movie SET movie_name ='$movie_name', movie_year = '$movie_year', movie_type ='$movie_type', movie_leadactor ='$movie_leadactor', movie_director ='$movie_director', movie_running_time ='$movie_time', movie_cost ='$movie_cost', movie_takings ='$movie_earn'";
并添加此项以检查错误:
if (!mysql_query($query))
{
die('Error: ' . mysql_error());
}
这应该完美无缺。