Question

我有以下代码，最终导致分段错误。

import ctypes
from random import randint

class STRUCT_2(ctypes.Structure):
    #_pack_=2
    _fields_ = [('field_1', ctypes.c_short),
                ('field_2', ctypes.c_short),
                ('field_3', ctypes.c_short)]

class STRUCT_1(ctypes.Structure):
    #_pack_=2
    _fields_ = [('elements', ctypes.c_short),
                ('STRUCT_ARRAY', ctypes.POINTER(STRUCT_2))]

    def __init__(self,num_of_structs):
        elems = (ctypes.POINTER(STRUCT_2) * num_of_structs)()
        self.STRUCT_ARRAY = ctypes.cast(elems,ctypes.POINTER(STRUCT_2))
        self.elements = num_of_structs

        for num in range(0,num_of_structs):
            self.STRUCT_ARRAY[num].field_1 = 1
            self.STRUCT_ARRAY[num].field_2 = 2
            self.STRUCT_ARRAY[num].field_3 = 3

for num in range(0,100):
    test = STRUCT_1(num)
    print "%i done" % num

输出： 5完成了分段错误

但是如果struct_2中没有field_3那么它似乎正常工作。如果我添加一个短字段（field_4），它会结束分段错误...

那么我做错了什么或者我错过了什么？

还有其他方法来定义数组大小吗？

Answer 1

代码中的STRUCT_ARRAY应该是指向指针数组的指针，而不是指向数组中元素的指针，因为您要将STRUCT_2指针附加到数组。

在c中，STRUCT_ARRAY可以定义为* STRUCT_2 [length]，也就是STRUCT_2指针的数组

import ctypes
from random import randint

class STRUCT_2(ctypes.Structure):
    #_pack_=2
    _fields_ = [('field_1', ctypes.c_short),
                ('field_2', ctypes.c_short),
                ('field_3', ctypes.c_short),
                ('field_4', ctypes.c_short),
                ('field_5', ctypes.c_short),
                ('field_6', ctypes.c_short),
                ('field_7', ctypes.c_short),
                ('field_8', ctypes.c_short)]

class STRUCT_1(ctypes.Structure):
    #_pack_=2
    _fields_ = [('elements', ctypes.c_short),
                #an array of pointers
                ('STRUCT_ARRAY', ctypes.POINTER(ctypes.POINTER(STRUCT_2)))]

    def __init__(self,num_of_structs):
        elems = (ctypes.POINTER(STRUCT_2) * num_of_structs)()
        self.STRUCT_ARRAY = ctypes.cast(elems,ctypes.POINTER(ctypes.POINTER(STRUCT_2)))
        self.elements = num_of_structs

        for num in range(0,num_of_structs):
            self.STRUCT_ARRAY[num].field_1 = 1
            self.STRUCT_ARRAY[num].field_2 = 2
            self.STRUCT_ARRAY[num].field_3 = 3

for num in range(0,100):
    test = STRUCT_1(num)
    print("%i done" % num)

如果你想要的是一个结构数组，请使用以下代码：

import ctypes
from random import randint

class STRUCT_2(ctypes.Structure):
    #_pack_=2
    _fields_ = [('field_1', ctypes.c_short),
                ('field_2', ctypes.c_short),
                ('field_3', ctypes.c_short),
                ('field_4', ctypes.c_short),
                ('field_5', ctypes.c_short),
                ('field_6', ctypes.c_short),
                ('field_7', ctypes.c_short),
                ('field_8', ctypes.c_short)]

class STRUCT_1(ctypes.Structure):
    #_pack_=2
    _fields_ = [('elements', ctypes.c_short),
                #an array of structs
                ('STRUCT_ARRAY', ctypes.POINTER(STRUCT_2))]

    def __init__(self,num_of_structs):
        elems = (STRUCT_2 * num_of_structs)()
        self.STRUCT_ARRAY = ctypes.cast(elems,ctypes.POINTER(STRUCT_2))
        self.elements = num_of_structs

        for num in range(0,num_of_structs):
            self.STRUCT_ARRAY[num].field_1 = 1
            self.STRUCT_ARRAY[num].field_2 = 2
            self.STRUCT_ARRAY[num].field_3 = 3
            self.STRUCT_ARRAY[num].field_4 = 4

for num in range(0,100):
    test = STRUCT_1(num)
    print("%i done" % num)

python ctypes结构数组

1 个答案: