Question

我做了这个开关声明，当我按下按钮线时该部分工作，当我按下输入一次有效但但当我再次按它时，它不是为什么？

@Override
public void onClick(View v) {
    // TODO Auto-generated method stub
    OutPutConversion Out = new OutPutConversion();
    DrawingTools AddL = new DrawingTools();
    EditText cl = (EditText) findViewById(R.id.CL);
    TextView info = (TextView) findViewById(R.id.info);
    int n = 0;
    switch (v.getId()) {
    case R.id.LineVL:
        info.setText("Enter x,y,z For Point 1");
        break;
    case R.id.Enter:
        switch (n) {
        case (0):
            String Input1 = cl.getText().toString();
            AddL.AddLine(Input1);
            info.setText("Enter x,y,z For Point 2");
            n++;
            break;
        case (1):
            String Input2 = cl.getText().toString();
            AddL.AddLine(Input2);
            info.setText("Press Enter Again TO See Results");
            n++;
            break;
        case (2):
            n = 0;
            Out.Out();
            break;
        }

Answer 1

删除int n=0;外部功能。截至目前，每次都将值重新设置为0.

我的switch语句出了什么问题？

1 个答案: