我的网址字符串是
“https://MyCom.Produect.App.ResourcePath/ts?Customer_Account=A B C \,LLC,D E F \,LLC& Billing_Code = 11,12& fromDateTime = 2013-05-13& toDateTime = 2013-06-13”
如果我在IE中复制并运行,它将返回一些数据。 但是c#中的相同字符串给我一个错误的请求异常。 这是我的c#代码,我想我必须错过一些东西。谢谢
public void GetDataAsyn(string m_strUrl)
{
var username = m_strEmail;
var password = m_strPassword;
var uri = new Uri(m_strUrl);
var credentialCache = new CredentialCache();
credentialCache.Add(uri, "Basic", new NetworkCredential(username, password));
var httpRequest = (HttpWebRequest)WebRequest.Create(uri);
httpRequest.Method = "GET";
httpRequest.ContentType = "application/json";
httpRequest.UseDefaultCredentials = true;
httpRequest.Accept = Constants.CONTENT_TYPE_TEXT_CSV;
httpRequest.UserAgent = Helper.GetUserAgent();
Helper.SetProxyIfNeeded(httpRequest, uri);
httpRequest.Headers.Add("Authorization", Helper.GetAuthHeader(username, password));
ServicePointManager.ServerCertificateValidationCallback = delegate { return true; };
httpRequest.BeginGetResponse(GetResponseCallback, new object[] { httpRequest });
}
private void GetResponseCallback(IAsyncResult asyncResult)
{
try
{
var obj = (object[])asyncResult.AsyncState;
var request = (HttpWebRequest)obj[0];
var response = request.EndGetResponse(asyncResult);
Stream responseStream = response.GetResponseStream();
if (responseStream != null)
{
var streamReader = new StreamReader(responseStream);
ReturnedData = streamReader.ReadToEnd();
}
....do something with ReturnedData
}
catch (Exception ex)
{
Helper.LogError(ex);
}
}
答案 0 :(得分:1)
我将在黑暗中拍摄,因为您没有告诉我们您如何将您的网址分配给m_strUrl
。
很可能你收到了错误的请求,因为C#中的\
字符是一个转义。
要解决此类问题,您必须要逃避\
这样的\\
或者更简洁的方法是使用@
符号并使字符串成为文字。
如果您提供的示例中的\
是网址的一部分(不是转义字符),则以下是您的文字网址字符串:
string m_strUrl = @"https://MyCom.Produect.App.ResourcePath/ts?Customer_Account=A%20B%20C\,%20LLC,D%20E%20F\,%20LLC&Billing_Code=11,12&fromDateTime=2013-05-13&toDateTime=2013-06-13";
如果您已经尝试使用\
来删除逗号,那么您的字符串将如下所示。
string m_strUrl = @"https://MyCom.Produect.App.ResourcePath/ts?Customer_Account=A%20B%20C,%20LLC,D%20E%20F,%20LLC&Billing_Code=11,12&fromDateTime=2013-05-13&toDateTime=2013-06-13";