我在Netbeans 7.3中制作了简单的helloworld。但我有负载jsp与控制器的值有问题。我部分启发了http://www.tutorialspoint.com/spring/spring_tutorial.pdf(第141页)的说明。但是当我想要在控制器中设置的值加载jsp时,不显示值。在控制器中捕获GET请求。我输入了这个网址:http://localhost:8080/HelloWorld3/hello.htm
。我得到了jsp,但没有显示值。当我输入上面教程中写的url时:
http://localhost:8080/HelloWeb/hello
,我收到404错误,找不到此页面。
我必须输入什么网址或者我做得更糟?我想这个错误是在一些配置文件中。谢谢
applicationContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation=" http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="cz.ryska.controllers"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
dipatcher-servlet.xml中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
<prop key="hello.htm">helloController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
<bean name="helloController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="hello" />
</beans>
的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
</web-app>
控制器:
@Controller
@RequestMapping("/hello")
public class HelloController {
@RequestMapping(method = RequestMethod.GET)
public String printHello(ModelMap model) {
model.addAttribute("message", "Hello Spring MVC Framework!");
return "hello";
}
}
的hello.jsp:
<%@page contentType="text/html; charset=UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<title>JSP Page</title>
</head>
<body>
<h1>Hello!!!!!!</h1>
<h2>${message}</h2>
</body>
</html>
答案 0 :(得分:1)
试试这个
@Controller
@RequestMapping("/hello")
public class MyController {
@RequestMapping(method = RequestMethod.GET)
public String sayHello(ModelMap model) {
model.addAttribute("message", "Spring 3 MVC Hello World");
return "hello";
}
}
的hello.jsp
<html>
<body>
<h1>Message : ${message}</h1>
</body>
的web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/dispatcher-servlet.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
调度-servlet.xml中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.gemini.spring.mvc"/>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
</beans>
答案 1 :(得分:0)
您是否有某种特殊原因以您的方式编写了helloWorld应用程序? 对于一个简单的helloWorld应用程序来说,它看起来似乎很复杂。
除非您有某种特定原因,否则您根本不需要定义两个独立的控制器。
我还完成了你链接的tutorialspoint示例,并且我的工作完美,但它是原始示例的克隆。
如果你想扩展或玩弄这个例子,我建议你先克隆这个例子然后让它运转起来......然后从那里继续前进,一步一步。
虽然我没有在我面前提出解决方案,但Georgy Gobozov给出的答案看起来是正确的。