召集所有NHibernate大师!
如果你们中的任何一个聪明人都能帮助我解决以下难题,我将非常感激:
我有一些实体描述来自各种来源的RSS源,这些源在一个名为FeedList的实体中组合在一起。
我试图仅选择与给定FeedList链接的不同SourceFeed实体。 (即“WHERE FeedList.name ='feedlist1'”。
我一直在玩JoinQueryOver一段时间,但我似乎无法弄清楚如何获得所需的结果。
实体的相关性如下:
FeedList>饲料> FeedSource
因此FeedList包含许多Feed,每个Feed都属于FeedSource。
以下是实体的代码:
public class Feed
{
public virtual int Id { get; set; }
public virtual string Description { get; set; }
public virtual FeedSource FeedSource { get; set; }
public virtual string URL { get; set; }
}
public class FeedList
{
public virtual int Id{get;set;}
public virtual string Name { get; set; }
public virtual IList<Feed> Feeds { get; set; }
}
public class FeedSource
{
public virtual int Id { get; set; }
public virtual string Name { get; set; }
}
我使用Fluent Automapping并使用以下覆盖:
public class FeedOverride : IAutoMappingOverride<Feed>
{
public void Override(AutoMapping<Feed> mapping)
{
mapping.References<FeedSource>(map => map.FeedSource).Cascade.All();
}
}
public class FeedListOverride : IAutoMappingOverride<FeedList>
{
public void Override(AutoMapping<FeedList> mapping)
{
mapping.HasManyToMany<Feed> (map => map.Feeds).Cascade.All().Table("FeedList_Feed");
}
}
以下是一些创建一些示例数据的代码:
private static void CreateSampleData()
{
using (var session = HibernateHelper.OpenSession())
{
using (var transaction = session.BeginTransaction())
{
//Create source 1 and feeds
FeedSource source1 = new FeedSource() { Name = "BBC" };
IList<Feed> feedsForSource1 = new List<Feed>(){
CreateFeed("Sample Feed1",source1,"http://feed1.xml"),
CreateFeed("Sample Feed2",source1,"http://feed2.xml")
};
FeedList feedList1 = CreateFeedList("FeedList1", feedsForSource1);
//Create source 2 and feeds
FeedSource source2 = new FeedSource() { Name = "Sky" };
IList<Feed> feedsForSource2 = new List<Feed>(){
CreateFeed("Sample Feed3",source2,"http://feed3.xml"),
CreateFeed("Sample Feed4",source2,"http://feed4.xml"),
CreateFeed("Sample Feed5",source2,"http://feed5.xml")
};
FeedList feedList2 = CreateFeedList("FeedList2", feedsForSource2);
session.SaveOrUpdate(feedList1);
session.SaveOrUpdate(feedList2);
transaction.Commit();
}
}
}
我想要实现的目标是什么?
如果我在SQL中描述它(非常糟糕),我希望做这样的事情:
select distinct *
from FeedList as list
LEFT JOIN FeedList_Feed as list_feed
ON list.Id = list_feed.FeedList_id
LEFT JOIN Feed as feed
ON feed.FeedSource_id = list_feed.Feed_id
LEFT JOIN FeedSource as src
ON src.Id = list_feed.Feed_id
WHERE list.Name="a feedlist name"
非常感谢您的时间:)
答案 0 :(得分:1)
好的,所以我终于成功地为所有感兴趣的人解决了这个问题:
<强>实体强>
public class Feed
{
public virtual int Id { get; set; }
public virtual string Description { get; set; }
public virtual FeedSource FeedSource { get; set; }
public virtual string URL { get; set; }
public virtual FeedList FeedList { get; set; }
}
public class FeedList
{
public virtual int Id{get;set;}
public virtual string Name { get; set; }
public virtual IList<Feed> Feeds { get; set; }
}
public class FeedSource
{
public virtual int Id { get; set; }
public virtual string Name { get; set; }
}
<强>覆盖强>
public class FeedOverride : IAutoMappingOverride<Feed>
{
public void Override(AutoMapping<Feed> mapping)
{
mapping.References<FeedList>(map => map.FeedList).Cascade.All();
mapping.References<FeedSource>(map => map.FeedSource).Cascade.All();
}
}
public class FeedListOverride : IAutoMappingOverride<FeedList>
{
public void Override(AutoMapping<FeedList> mapping)
{
mapping.HasManyToMany<Feed>(map => map.Feeds).Cascade.All().Table("FeedList_Feed");
//mapping.HasMany<FeedListFeed>(map => map.Feeds).Cascade.All();
}
}
最后:
查询
session.QueryOver<FeedList>()
.Inner.JoinAlias(f => f.Feeds, () => feedAlias)
.Where(fl => fl.Name == name)
.Select(x => feedAlias.FeedSource)
.List<FeedSource>().Distinct().ToList();