Question

我有两个WinForms NET应用程序“Test.exe”，资源“WindowsFormsApplication1.exe”。资源被标记为“嵌入式”。程序资源 - 空白项目Winforms（只有表单和没有处理程序的按钮）。使用“Test.exe”中的常用代码：

 private void button1_Click(object sender, EventArgs e)
        {
            this.Hide();
            RunInternalExe("WindowsFormsApplication1.exe");
        }
   private static void RunInternalExe(string exeName)
        {
            //Get the current assembly
            Assembly assembly = Assembly.GetExecutingAssembly();

            //Get the assembly's root name
            string rootName = assembly.GetName().Name;

            //Get the resource stream
            Stream resourceStream = assembly.GetManifestResourceStream(rootName + "." + exeName);

            //Verify the internal exe exists
            if (resourceStream == null)
                return;

            //Read the raw bytes of the resource
            byte[] resourcesBuffer = new byte[resourceStream.Length];

            resourceStream.Read(resourcesBuffer, 0, resourcesBuffer.Length);
            resourceStream.Close();

            //Load the bytes as an assembly
            Assembly exeAssembly = Assembly.Load(resourcesBuffer);

            //Execute the assembly
            exeAssembly.EntryPoint.Invoke(null, null); //no parameters
        }

当尝试从资源运行EXE时出现错误：行上的“TargetInvocationException”：

 exeAssembly.EntryPoint.Invoke(null, null);

Answer 1

我找到了解决方案。资源程序中的表单是在同一个线程中创建的。在这种情况下，我需要使用这样的代码：

    private void button1_Click(object sender, EventArgs e)
        {
        this.Hide();
        Thread t = new Thread(new ParameterizedThreadStart(RunInternalExe));
        t.Start("RunCodeFromDll.exe");

        //RunInternalExe("RunCodeFromDll.exe");
        }
    static void RunInternalExe(object tempName)
        {
        string exeName = tempName.ToString();
        //Get the current assembly
        Assembly assembly = Assembly.GetExecutingAssembly();

        //Get the assembly's root name
        string rootName = assembly.GetName().Name;

        //Get the resource stream
        Stream resourceStream = assembly.GetManifestResourceStream(rootName + "." + exeName);

        //Verify the internal exe exists
        if (resourceStream == null)
            return;

        //Read the raw bytes of the resource
        byte[] resourcesBuffer = new byte[resourceStream.Length];

        resourceStream.Read(resourcesBuffer, 0, resourcesBuffer.Length);
        resourceStream.Close();

        //Load the bytes as an assembly
        Assembly exeAssembly = Assembly.Load(resourcesBuffer);

        //Execute the assembly
        exeAssembly.EntryPoint.Invoke(null, null); //.EntryPoint.Invoke(null, null); //no parameters
        }

我应该更加小心。）））

从资源运行EXE时出错

1 个答案: