Question

Name = []
Address = []
for a in range(1):
    Name = raw_input ('Enter Name: ')
    Address = raw_input ('Enter Address: ')
    print Name
    print Address
    print [dict(zip(Name, e)) for  e in Address]
    a +=1

这就是我得到的

Enter Name: Kapil
Enter Address: Soni
Kapil
Soni
[{'K': 'S'}, {'K': 'o'}, {'K': 'n'}, {'K': 'i'}]

我想创建如下

{'Kapil':'Soni'}

我做错了什么？

Answer 1

您使用相同的名称列表和输入变量来保存单个名称。试试这个：

name_address_pairs = []

for a in range(1):
    name = raw_input ('Enter Name: ')
    address = raw_input ('Enter Address: ')
    print name
    print address
    name_address_pairs.append( { name: address } )

（作为旁注，变量名应按惯例以小写字母开头。）

Answer 2

addressbook = {}
for a in range(1):
    name = raw_input ('Enter Name: ')
    address = raw_input ('Enter Adress: ')
    addressbook[name] = address
print addressbook

names = []
addresses = []
for a in range(1):
    name = raw_input ('Enter Name: ')
    address = raw_input ('Enter Adress: ')
    names.append(name)
    addresses.append(address)
print dict(zip(names, addresses))

Answer 3

您正在定义Name = []，然后分配Name = input()，将数据类型更改为字符串。

此外，压缩字符串会将字符串转换为列表。例如

print zip('foo','bar')
# will produce
[('f', 'b'), ('o', 'a'), ('o', 'r')]

您想要做的只是

# in the beginning
address_book = []

# and in your loop
print { Name : Address }
address_book[ Name ] = Address

Answer 4

有一种简单的方法可以做到这一点：

print "{",Name,":",Address,"}"

如果要将收到的所有输入添加到单个词典中，请执行以下操作：

dictionary={}
for a in range(20):
    Name=raw_input()
    Address=raw_input()
    dictionary[Name]=Address

为什么列表中的字典是分开的

4 个答案: