一次获取n个字符组

Question

我正在尝试将字符串分组为三个（但可以是任意数字）字符。使用此代码：

"this gets three at a time".scan(/\w\w\w/)

我明白了：

["thi","get","thr","tim"]

但我想要的是：

["thi","sge","tst","hre","eat","ati","me"]

Answer 1

\w匹配字母数字和下划线（即它是[a-zA-Z0-9_]的简写），而不是空格。然而，正如您所期待的那样，它并没有神奇地跳过空格。

所以你首先要删除这些空格：

"this gets three at a time".gsub(/\s+/, "").scan(/.../)

或非单词字符：

"this gets three at a time".gsub(/\W+/, "").scan(/.../)

在匹配三个字符之前

。

虽然你应该使用

"this gets three at a time".gsub(/\W+/, "").scan(/.{1,3}/)

也可以获得最后的1或2，如果长度不能被3整除。

Answer 2

 "this gets three at a time".tr(" \t\n\r", "").scan(/.{1,3}/)

Answer 3

您也可以尝试这些：

sentence = "this gets three at a time"
sentence[" "] = ""
sentence.scan(/\w\w\w/)  // no change in regex

或者：

sentence = "this gets three at a time"
sentence[" "] = ""
sentence.scan(/.{1,3}/)   

或者：

sentence = "this gets three at a time"
sentence[" "] = ""
sentence.scan(/[a-zA-Z]{1,3}/)