Question

我正在尝试从列表中读取并在dict中返回相应的值。我帮我错了。谢谢

DICT = {"b": "21", "g": "54", "f": "121", "t": "1", "j": "33"}
n = ['b', 'w', 'f']

for keys in n:
    if keys in n:
        if n == DICT.keys():
            print(DICT.values())
        else:
            if keys not in n:
                print('Not Available')

Answer 1

for key in n:
    if key in dict.keys():
        print(dict[key])

似乎这就是你要做的事情

Answer 2

如果您使用get

，则非常简单

for k in n:
    print(DICT.get(k, 'Not Available'))

Answer 3

如果使用get（）方法，这将更容易：

DICT = {"b": "21", "g": "54", "f": "121", "t": "1", "j": "33"}
n = ['b', 'w', 'f']


for key in n:
    if DICT.get(key):
        print(DICT[key])
    else:
        print("Not available")

它产生了以下输出：

21
不适用
121

Answer 4

你正在迭代n的所有元素，但是检查n是否是每个循环的字典的所有键，它不是。试着这样做：

for key in n:
    if key in DICT:
        print(DICT[key])
    else:
        print('not available')

Answer 5

>>>for keys in n:
       if keys in DICT.keys():
           print DICT[keys]
       else:
           print ('Not Available')

21
Not Available
121

Answer 6

print '\n'.join((DICT[key] for key in n if key in DICT))

循环返回dict中的值的列表

6 个答案: