Question

我的SQL语句不起作用......

这是我的变量：

$email="test@test.com";

这些陈述不起作用：

$sql = "SELECT * FROM table WHERE email = $email";
$sql = 'SELECT * FROM table WHERE email = ' . $email;

1064您的SQL语法有错误;查看与MySQL服务器版本对应的手册，以便在第1行的“@ test.com”附近使用正确的语法

但是如果我使用字符串而不是变量，它可以工作：

$sql = "SELECT * FROM table WHERE email = 'test@test.com'";

我的陈述有什么问题？谢谢！

Answer 1

请在mysql中转义字符串

$sql = "SELECT * FROM table WHERE email = $email"; 
$sql = 'SELECT * FROM table WHERE email = ' . $email;

这应该有效

$sql = "SELECT * FROM table WHERE email = '$email'";

Answer 2

table是一个关键字，所以可以像这样写

$sql = "SELECT * FROM `table` WHERE email='$email'";

Answer 3

 $this->db->where('email', $this->input->post('email'));
    $query =$this->db->get($this->user);

  //$sql = "SELECT * FROM  user WHERE email = '$email'"; 
if($query->num_rows == 1)
{
    return true;
}
else
{
    return false;
}

} }

SQL语句不起作用SELECT 1064 SQL语法错误

3 个答案: