我有一个循环函数，它在前5秒运行social1()，在第5秒运行social2()然后循环...
我也有2个悬停功能
我需要清除所有有效超时，因为当我将鼠标悬停在图像上时（ .social1 ＆amp; .social2 ），我可以看到多个超时正在运行
如何解决这个问题？
function social1() {
$('.social1').fadeTo(500, 1);
$('.social2').fadeTo(500, 0.5);
timeout = setTimeout(function() {
social2();
}, 5000);
}
function social2() {
$('.social1').fadeTo(500, 0.5);
$('.social2').fadeTo(500, 1);
timeout = setTimeout(function() {
social1();
}, 5000);
}
$(document).ready(function ()
{
social1();
$('.social1').hover(
function () {
window.clearTimeout(timeout);
social1();
},
function () {
timeout = setTimeout(function() {
social2();
}, 5000);
}
);
$('.social2').hover(
function () {
window.clearTimeout(timeout);
social2();
},
function () {
timeout = setTimeout(function() {
social1();
}, 5000);
}
);
答案 0 :(得分：28)
要管理超时（和间隔）的集合，您可以使用以下代码段。 这将允许清除代码中任何位置设置的任何超时或间隔，但是，您必须在设置任何超时或间隔之前设置此代码段。基本上，在处理任何使用超时/间隔的javascript代码或外部脚本之前。
<强> JS：
;(function () {
window.timeouts = {},
window.intervals = {},
window.osetTimeout = window.setTimeout,
window.osetInterval = window.setInterval,
window.oclearTimeout = window.clearTimeout,
window.oclearInterval = window.clearInterval,
window.setTimeout = function () {
var args = _parseArgs('timeouts', arguments),
timeout = window.osetTimeout.apply(this, args.args);
window.timeouts[args.ns].push(timeout);
return timeout;
},
window.setInterval = function () {
var args = _parseArgs('intervals', arguments),
interval = window.osetInterval.apply(this, args.args);
window.intervals[args.ns].push(interval);
return interval;
},
window.clearTimeout = function () {
_removeTimer('timeouts', arguments);
},
window.clearInterval = function () {
_removeTimer('intervals', arguments);
},
window.clearAllTimeout = function () {
_clearAllTimer('timeouts', arguments[0]);
},
window.clearAllInterval = function () {
_clearAllTimer('intervals', arguments[0]);
};
function _parseArgs(type, args) {
var ns = typeof args[0] === "function" ? "no_ns" : args[0];
if (ns !== "no_ns")[].splice.call(args, 0, 1);
if (!window[type][ns]) window[type][ns] = [];
return {
ns: ns,
args: args
};
}
function _removeTimer(type, args) {
var fnToCall = type === "timeouts" ? "oclearTimeout" : "oclearInterval",
timerId = args[0];
window[fnToCall].apply(this, args);
for (var k in window[type]) {
for (var i = 0, z = window[type][k].length; i < z; i++) {
if (window[type][k][i] === timerId) {
window[type][k].splice(i, 1);
if (!window[type][k].length) delete window[type][k];
return;
}
}
}
}
function _clearAllTimer(type, ns) {
var timersToClear = ns ? window[type][ns] : (function () {
var timers = [];
for (var k in window[type]) {
timers = timers.concat(window[type][k]);
}
return timers;
}());
for (var i = 0, z = timersToClear.length; i < z; i++) {
_removeTimer(type, [timersToClear[i]]);
}
}
}());
像往常一样设置超时/间隔：
var test1 = setTimeout(function(){/**/, 1000);
var test2 = setTimeout(function(){/**/, 1000);
然后你可以用来清除这两个：
clearAllTimeout(); // clearAllInterval(); for intervals
这将清除两次超时（test1＆amp; test2）
您可以使用某些命名空间来仅清除特定的计时器，例如：
// first (optional) parameter for setTimeout/setInterval is namespace
var test1 = setTimeout('myNamespace', function(){/**/, 1000); // 'myNamespace' is current namespace used for test1 timeout
var test2 = setTimeout(function(){/**/, 1000); // no namespace used for test2 timeout
同样，clearAllTimeout();将清除两个超时。要仅清除命名空间的一个，您可以使用：
clearAllTimeout('myNamespace'); // clearAllInterval('myNamespace'); for namespaced intervals
这将仅清除test1超时
您可以出于某种原因希望仅删除非命名空间超时。然后你可以使用：
clearAllTimeout('no_ns'); // clearAllInterval('no_ns'); for non namespaced intervals only
这将在此示例中仅清除test2超时
编辑的
您可以尝试：
var timeouts = [];
timeouts.push(setTimeout(function() {
social2();
}, 5000));
timeouts.push(setTimeout(function() {
social1();
}, 5000));
//etc...
function clearAllTimeouts(){
for(var i = 0, z = timeouts.length; i < z; i++)
clearTimeout(timeouts[i]);
timeouts = [];
}
David Thomas评论后更新
var timeouts = {'social' : [], 'antisocial' : []};
//a social timeout
timeouts.social.push(setTimeout(function() {
social1();
}, 5000));
//an anti-social timeout
timeouts.antisocial.push(setTimeout(function() {
antisocial1();
}, 5000));
function clearTimeouts(namespace){
for(var i = 0, z = timeouts[namespace].length; i < z; i++)
clearTimeout(timeouts[namespace][i]);
timeouts[namespace] = [];
}
//usage e.g
clearTimeouts("social");
答案 1 :(得分：0)
//Incase if you are looking for full fledged code
var dict = {};
function checkForIntervals(id){
var index = index;
var result = findOrAddProperty(id);
if(result.length != 0){
clearTimeoutsFor(id);
}
dict[id].push(setTimeout(function(){alertFunc(id,index);}, 60000));
};
// to clear specific area timeout
function clearTimeoutsFor(namespace){
for(var i = 0, z = dict[namespace].length; i < z; i++)
clearTimeout(dict[namespace][i]);
dict[namespace] = [];
}
to clear all timeouts
function clearAllTimeOuts(){
for (key in dict) {
for(var i = 0, z = dict[key].length; i < z; i++)
clearTimeout(dict[key][i]);
dict[key] =[];
}
};
function findOrAddProperty(str){
var temp = [];
for (key in dict) {
if(key == str){
if (dict.hasOwnProperty(key)) {
temp = dict[key];
break;
}
}
}
if(temp.length == 0){
dict[str] = [];
}
return temp;
};
function alertFunc(id,index) {
jQuery(document).ready(function($) {
do the ajax call here after 1 min
});
};