我想在文本中进行正则表达式搜索,我想跳过文本中的某些字符。这里问的原始问题是:Regular Expression library that maintains state, takes input character by character and returns true whenever match is found为此,我创建了一个自定义迭代器,并尝试将这些迭代器传递给regex_iterator。但我得到以下错误:
regex(2775): error C2512: 'fixed_array::iterator' : no appropriate default constructor available
with
[
T=char
]
regex(2773) : while compiling class template member function 'std::tr1::regex_iterator::regex_iterator(void)'
with
[
_BidIt=fixed_array::iterator
]
iterator.cpp(168) : see reference to class template instantiation 'std::tr1::regex_iterator' being compiled
with
[
_BidIt=fixed_array::iterator
]
regex(2775): error C2512: 'fixed_array::iterator' : no appropriate default constructor available
with
[
T=char
]
这是我的代码:
template
class fixed_array
{
public:
typedef int size_type;
class iterator
{
public:
typedef iterator self_type;
typedef T value_type;
typedef T& reference;
typedef T* pointer;
typedef std::bidirectional_iterator_tag iterator_category;
typedef int difference_type;
iterator(pointer ptr) : ptr_(ptr) { }
self_type operator++() /*skip character 'a'*/
{
self_type i = *this;
ptr_++;
if(*ptr_ == 'a')
ptr_++;
return i;
}
self_type operator++(int junk)
{
ptr_++;
if(*ptr_ == 'a')
ptr_++;
return *this;
}
reference operator*()
{
return *ptr_;
}
pointer operator->()
{
return ptr_;
}
bool operator==(const self_type& rhs)
{
return ptr_ == rhs.ptr_;
}
bool operator!=(const self_type& rhs)
{
return ptr_ != rhs.ptr_;
}
private:
pointer ptr_;
};
class const_iterator
{
public:
typedef const_iterator self_type;
typedef T value_type;
typedef T& reference;
typedef T* pointer;
typedef int difference_type;
typedef std::bidirectional_iterator_tag iterator_category;
const_iterator(pointer ptr) : ptr_(ptr) { }
self_type operator++() { self_type i = *this; ptr_++; return i; }
self_type operator++(int junk) { ptr_++; return *this; }
const reference operator*() { return *ptr_; }
const pointer operator->() { return ptr_; }
bool operator==(const self_type& rhs) { return ptr_ == rhs.ptr_; }
bool operator!=(const self_type& rhs) { return ptr_ != rhs.ptr_; }
private:
pointer ptr_;
};
fixed_array(size_type size) : size_(size) {
data_ = new T[size_];
}
size_type size() const { return size_; }
T& operator[](size_type index)
{
assert(index < size_);
return data_[index];
}
const T& operator[](size_type index) const
{
assert(index < size_);
return data_[index];
}
iterator begin()
{
return iterator(data_);
}
iterator end()
{
return iterator(data_ + size_);
}
const_iterator begin() const
{
return const_iterator(data_);
}
const_iterator end() const
{
return const_iterator(data_ + size_);
}
private:
T* data_;
size_type size_;
};
using namespace std;
int main()
{
fixed_array<char> point3d(50);
//initialize the array with some string.
regex e ("a.*ea");
fixed_array<char>::iterator beg = point3d.begin();
fixed_array<char>::iterator end = point3d.end();
regex_iterator<fixed_array<char>::iterator> rit ( beg, end, e );
regex_iterator<fixed_array<char>::iterator> rend;
while (rit!=rend) {
cout << rit->str() << std::endl;
++rit;
}
return 0;
}
答案 0 :(得分:2)
过滤迭代器很难搞定。另外,你的const和非const迭代器是不一致的。
我建议您使用Boost filter_iterator而不是编写自己的东西。
答案 1 :(得分:0)
好的,最后在塞巴斯蒂安的回答和一些研究的帮助下,我能够实现我的目标。
我使用了以下页面中给出的过滤器迭代器代码: http://blogs.msdn.com/b/vcblog/archive/2010/08/09/the-filterator.aspx
以下是我在上面的迭代器中所写的内容:
struct is_current_charT {
bool operator()(char s) const {
return s != 't';
}
};
int main() {
using namespace std;
string str = "test1 ,,ktest2,, ktest3,, ktest0,,";
regex e ("kes[0-9]");
auto fit = make_filterator(str.begin(), str.end(),
is_current_charT());
filterator<string::iterator,is_current_charT> cdogs(fit);
regex_iterator<filterator<string::iterator,is_current_charT>> rit ( cdogs, cdogs.end(), e );
regex_iterator<filterator<string::iterator,is_current_charT>> rend;
while (rit!=rend) {
cout << rit->str() << std::endl;
++rit;
}
}
输出:
kes2
kes3
kes0
现在可以轻松修改它以编写更有意义的过滤功能。
感谢艾哈迈德,谢谢塞巴斯蒂安!