Question

我有一个带有JSON的文件：

{
    "first":{"a":[{"b":[{"c":"AAA"}]}],"d":111},
    "second":{"a":[{"b":[{"c":"BBB"},{"c":"CCC"}]}],"d":222}
}

我需要用平面文本结构保存它，类似的东西：

111
    AAA
222
    BBB
    CCC

如何迭代JSON？我所能做的就是：

import json

file_json = open('1.txt', mode='r', encoding='utf-8')
data = json.load(file_json)
file_json.close()

file_new = open('data.txt', mode='w', encoding='utf-8')

for number in data:
    file_new.write(number + "\n")

file_new.close()

我得到了

first
second

但我如何获得其他数据呢？我尝试了for number, data_rest in data:，但获得了ValueError: too many values to unpack (expected 2)。

Answer 1

对于这个特定的结构，您可以从

获取您正在寻找的元素

>>> d = {
...     "first":{"a":[{"b":[{"c":"AAA"}]}],"d":111},
...     "second":{"a":[{"b":[{"c":"BBB"},{"c":"CCC"}]}],"d":222}
... }
>>> d['first']['d']
111
>>> import itertools
>>> list(itertools.chain.from_iterable(x.values() for x in d['first']['a'][0]['b']))
['AAA']
>>> list(itertools.chain.from_iterable(x.values() for x in d['second']['a'][0]['b']))
['BBB', 'CCC']

当你说完所有时，它可能看起来像这样：

from itertools import chain
import json

s = '''{
    "first":{"a":[{"b":[{"c":"AAA"}]}],"d":111},
    "second":{"a":[{"b":[{"c":"BBB"},{"c":"CCC"}]}],"d":222}
}'''

from collections import OrderedDict
d = json.loads(s,object_pairs_hook=OrderedDict)  #Keep order of dictionaries

for subdict in d.values():
    print subdict['d']
    chained = chain.from_iterable(x.values() for x in subdict['a'][0]['b'])
    for item in chained:
        print '\t',item

从JSON中间获取数据

1 个答案: