我正在使用牛仔和jiffy(Json库)作为我的websocket ..我可以在我的websocket_handle中从客户端接收数据,截至目前我的代码与此类似
websocket_handle({text, Msg}, Req, Handle) ->
Message = jiffy:decode(Msg),
case Message of
pattern1 - > ........... pattern2 - > .......... 结束, {ok,Res,State}
然而,不是这样,我想在句柄级别模式匹配...
websocket_handle({text, pattern1}, Req, State),
websocket_handle({text, pattern2}, Req, State)
问题是我不能在websocket_handle的参数中使用jiffy:decode ...所以我不能写像
websocket_handle({text, jiffy:decode(Msg), Req, State})
如何使它工作?
答案 0 :(得分:5)
如果您喜欢函数签名与案例表达式中的模式匹配,您可以将解码后的消息“转发”到另一个“内部”函数。
websocket_handle({text, Msg}, Req, Handle) ->
Message = jiffy:decode(Msg),
websocket_handle_({test, Message}, Req, Handle).
websocket_handle_({text, Pattern1}, Req, Handle) ->
{ok, Req, State};
websocket_handle_({text, Pattern2}, Req, Handle) ->
{reply, OutFrame | [OutFrame], Req, State};
websocket_handle_({text, PatternN}, Req, Handle) ->
{ok, Req, State}.
答案 1 :(得分:1)
所以只需改为
websocket_handle({text, Msg}, Req, Handle) ->
websocket_handle_({text, jiffy:decode(Msg)}, Req, Handle).
websocket_handle_({text, Pattern1}, Req, Handle) ->
%% do stuff,
{ok, Req, State};
websocket_handle_({text, Pattern2}, Req, Handle) ->
%% do stuff,
{reply, [OutFrame], Req, State};
websocket_handle_({text, PatternN}, Req, Handle) ->
%% do stuff,
{reply, OutFrame, Req, State}.