Question

我有一个包含以数字开头的行的文件，例如

1 This is the first line
2 this is the second line
3 this is the third line
4 This is the fourth line

我想要做的是删除一行例如第2行并更新编号，以便文件如下所示，我想在bash脚本中执行此操作。

1 This is the first line
2 this is the third line
3 This is the fourth line

由于

Answer 1

使用awk IMO可能会更容易一些：

awk '!/regex/ {$1=++x; print}' inputFile

在/.../中，您可以将regex放在需要删除的行上。

测试：

$ cat inputFile
1 This is the first line
2 this is the second line
3 this is the third line
4 This is the fourth line

$ awk '!/second/ {$1=++x; print}' inputFile
1 This is the first line
2 this is the third line
3 This is the fourth line

$ awk '!/third/ {$1=++x; print}' inputFile
1 This is the first line
2 this is the second line
3 This is the fourth line

$ awk '!/first/ {$1=++x; print}' inputFile
1 this is the second line
2 this is the third line
3 This is the fourth line

注意：由于我们正在重新构建$1字段，因此将删除任何空格序列。

Answer 2

您可以使用以下命令集：

grep -v '^2 ' file | cut -d' ' -f2- | nl -w1 -s' '

使用grep和-v选项可以删除第2行。
cut程序会删除第一列，即行号。
最后，我们只需对行进行重新编号，以便我们使用nl。

删除行和更新订单

2 个答案:

测试：