根据另一个集合重新安排集合列表

Question

我有以下查询

neo4j-sh (?)$ 
$start n=node(*) match p=n-[r:LIKES]->items return n,collect(r.w),collect(items.name);
==> +------------------------------------------------------------------------------------------------------------------+
==> | n                    | collect(r.w)           | collect(items.name)   |
==> +------------------------------------------------------------------------------------------------------------------+
==> | Node[249]{name:"u1"} | [0,0.93]               | ["f5","f2"]           |
==> | Node[248]{name:"u2"} | [0,-0.76,1,-0.66]      | ["f4","f3","f2","f1"] |
==> +------------------------------------------------------------------------------------------------------------------+

我想根据r.w的排序值重新排序项目，如下所示

==> +------------------------------------------------------------------------------------------------------------------+
==> | n                    | collect(r.w)           | collect(items.name)   |
==> +------------------------------------------------------------------------------------------------------------------+
==> | Node[249]{name:"u1"} | [0.93,0]             | ["f2","f5"]           |
==> | Node[248]{name:"u2"} | [1,0,-0.66,-0.76]    | ["f2","f4","f1","f3"] |
==> +------------------------------------------------------------------------------------------------------------------+

如何根据collect（r.w）的排序值重新安排collect（items.name）的元素？

Answer 1

我认为可能就像这样

START n=node(*) 
MATCH p=n-[r:LIKES]->items
WITH n,r,items
ORDER BY r.w DESC, items.name DESC
RETURN n,collect(r.w),collect(items.name);

Answer 2

通过WITH管道您的搜索结果，然后对其进行排序。然后照常通过RETURN进行聚合。

START n=node(*) 
MATCH p=n-[r:LIKES]->items
WITH n,r,items
ORDER BY r.w DESC
RETURN n,collect(r.w),collect(items.name);