Question

这是gawk 4.0.0，在带有cygwin的Windows 7上运行。该程序被调用，如

gawk -f procjournal.gawk testdata

我有一些看起来像这样的数据：

"Date";"Type";"Amount";"Balance"
"6/11/2013 11:51:17 AM";"Transaction Tax";-427.5;399313884.46
"6/11/2013 11:51:17 AM";"Market Transaction";47500;399314311.96
"6/11/2013 11:12:42 AM";"Transaction Tax";-549.92;399266811.96
"6/11/2013 11:12:42 AM";"Market Transaction";61101.78;399267361.88

我想提取事务的行，从第1个字段中删除日期部分，然后将时间戳重新格式化为小数。我以为我可以用这个awk程序做到这一点：

FS=";"
OFS=";"
/Market Transaction/ {
    split($1, itemdate, " ");
    tmp = itemdate[2];
    split(tmp, hms, ":");
    timestamp = hms[3] + (hms[2] * 60) + (hms[1] * 3600);
    if (itemdate[3] == "AM")
       timestamp += 12 * 3600;
    timestamp /= 3600.0;
    $1 = timestamp;
    print;
}

但我的输出如下：

"Date";"Type";"Amount";"Balance"
"Date";"Type";"Amount";"Balance"
"6/11/2013 11:51:17 AM";"Transaction Tax";-427.5;399313884.46
"6/11/2013 11:51:17 AM";"Transaction Tax";-427.5;399313884.46
"6/11/2013 11:51:17 AM";"Market Transaction";47500;399314311.96
"6/11/2013 11:51:17 AM";"Market Transaction";47500;399314311.96
11.8547;"Market Transaction";47500;399314311.96
"6/11/2013 11:12:42 AM";"Transaction Tax";-549.92;399266811.96
"6/11/2013 11:12:42 AM";"Transaction Tax";-549.92;399266811.96
"6/11/2013 11:12:42 AM";"Market Transaction";61101.78;399267361.88
"6/11/2013 11:12:42 AM";"Market Transaction";61101.78;399267361.88
11.2117;"Market Transaction";61101.78;399267361.88

为什么要打印不匹配的行，我该如何抑制它？

Answer 1

更改脚本以在BEGIN块中包含分隔符。

脚本内容：

BEGIN {
FS=";"
OFS=";"
}
/Market Transaction/ {
    split($1, itemdate, " ");
    tmp = itemdate[2];
    split(tmp, hms, ":");
    timestamp = hms[3] + (hms[2] * 60) + (hms[1] * 3600);
    if (itemdate[3] == "AM")
       timestamp += 12 * 3600;
    timestamp /= 3600.0;
    $1 = timestamp;
    print;
}

Answer 2

不是您问题的答案，而是计算时间的另一种方式：

if (match($1, /([0-9]?[0-9]):([0-9][0-9]):([0-9][0-9]) ([AP]M)/, a)) {
    $1 = a[1] + (a[2]*60 + a[3])/3600 + (a[4] == "PM" ? 12 : 0)
}

如何在awk中禁止默认打印？

2 个答案: