Question

我有一个文件夹区域，每个文件夹中有数百个文档，结构如下：

C:\myLibrary\Accident Investigation Report
C:\myLibrary\Address Change
C:\myLibrary\Medical Certificate
C:\myLibrary\New Starter

这些文件夹中的文件名称如下例所示（基于日期戳，时间戳，部门编号，报告类型，员工姓名）。

2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.xml
2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.pdf

2013-06-11 15-38-07 147 Address Change - L Test.xml
2013-06-11 15-38-07 147 Address Change - L Test.pdf

等

（每个都在他们自己明显的标题文件夹中）

识别文件来自哪个部门号码（重要位）是日期戳后面的数字＆amp;时间戳 - 在上面的例子中是165＆amp;分别为147。

我想根据他们的部门号码将所有文件移动到另一个设置文件夹结构（已经创建了）（每个部门都有另一个类似的结构如下所示）;

C:\Dept Structure\165man\Accident Investigation Report
C:\Dept Structure\165man\Address Change

等

因此，正如批处理文件运行后的上述示例文件一样，我应该最终得到;

C:\Dept Structure\165man\Accident Investigation Report\2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.pdf
C:\Dept Structure\165man\Accident Investigation Report\2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.xml
C:\Dept Structure\165man\Address Change\2013-06-06 16-28-59 165 Address Change - J Bloggs.pdf
C:\Dept Structure\165man\Address Change\2013-06-06 16-28-59 165 Address Change - J Bloggs.xml

C:\Dept Structure\147man\Accident Investigation Report\2013-06-11 15-38-07 147 Accident Investigation Report - L Test.pdf
C:\Dept Structure\147man\Accident Investigation Report\2013-06-11 15-38-07 147 Accident Investigation Report - L Test.xml
C:\Dept Structure\147man\Address Change\2013-06-11 15-38-07 147 Address Change - L Test.pdf
C:\Dept Structure\147man\Address Change\2013-06-11 15-38-07 147 Address Change - L Test.xml

我有一个包含所有部门经理编号的文本文件，例如

003man
004man
005man
006man
007man
008man
009man
etc
etc
410man

由此我想循环遍历文本文件，根据前3位数创建变量，添加＆＃39; Accident＆＃39;或者到这个变量的末尾，检查第一个C：\ myLibrary \事故调查报告＆＃39;在文件夹中，找到标题中包含该变量的任何文件，并将其移至“结构”部分＆＃39;上面命名的目录 - phew !!

我设法找到一些几乎＆＃39;完成这看起来非常简单;

`cd /D "C:\Test"`

`for /F %%i in (C:\Dept.txt) do set str1=%%i`

`set _dept=%str1%`
`set _dept=%_dept:~0,3%`
`set "str2=%_dept%`

`move "????????????????????%str2%*.*" "C:\Dept Structure\%str1%\Accident Investigation Report"`

它确实会将一些文件移动到正确的位置，但是，这似乎贯穿整个文本文件并且只处理最后一行！因此，所有其他行都保持不变，剩下的文件也没有移动。

Answer 1

测试 - 顶部创建测试文件和文件夹。然后它会移动文件，因为您似乎希望它们被移动。

@echo off
md "c:\mylibrary2\Accident Investigation Report\" 2>nul
md "c:\mylibrary2\Address Change\" 2>nul
type nul > "c:\mylibrary2\Accident Investigation Report\2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.pdf"
type nul > "c:\mylibrary2\Accident Investigation Report\2013-06-06 16-28-59 165 Accident Investigation Report - J Bloggs.xml"
type nul > "c:\mylibrary2\Address Change\2013-06-06 16-28-59 165 Address Change - J Bloggs.pdf"
type nul > "c:\mylibrary2\Address Change\2013-06-06 16-28-59 165 Address Change - J Bloggs.xml"
type nul > "c:\mylibrary2\Accident Investigation Report\2013-06-11 15-38-07 147 Accident Investigation Report - L Test.pdf"
type nul > "c:\mylibrary2\Accident Investigation Report\2013-06-11 15-38-07 147 Accident Investigation Report - L Test.xml"
type nul > "c:\mylibrary2\Address Change\2013-06-11 15-38-07 147 Address Change - L Test.pdf"
type nul > "c:\mylibrary2\Address Change\2013-06-11 15-38-07 147 Address Change - L Test.xml"



for /f "delims=" %%a in ('dir "c:\mylibrary2" /a-d /b /s') do (
for /f "tokens=3" %%b in ("%%~nxa") do (
for /f "delims=" %%c in ("%%~dpa\.") do (
md "C:\Dept Structure2\%%bman\%%~nxc\" 2>nul
move "%%a" "C:\Dept Structure2\%%bman\%%~nxc\" >nul
)
)
)

Answer 2

对不起。我不明白dept管理器数字文件用于什么。如果没有所有行的文件，则处理此列表中的所有行是浪费时间。如果文件不在此列表中并且您想省略它们，则此文件将非常有用，但您没有提及此点。

有几种方法可以解决这个问题。下面的批处理文件假定您在问题中解释的所有名称都没有错误。

@echo off
setlocal EnableDelayedExpansion

rem Process all folders in:
cd "C:\Dept Structure"
for /D %%a in (*) do (
   set "dept=%%a"                         // For example: "165man"
   set "dept=!dept:~0,3!"                 // For example: "165"
   pushd %%a
   rem Process all folders here, ie: "Accident Investigation Report" "Address Change"
   for /D %%b in (*) do (
      rem Move all existent files from source folder to this folder
      move "C:\myLibrary\%%b\*!dept! %%b - *.*" "%%b" 2> NUL
   )
   popd
)

批处理文件循环文本文件的内容，创建变量并移动具有部分名称的文件

2 个答案: