Question

嗨我想将 Via Me 社交网站整合到我的iphone应用程序中，我用谷歌搜索但没有找到任何样本。

Answer 1

基本流程如下：

为您的应用创建custom URL scheme。 Via Me将在用户通过身份验证后使用此功能，以返回到您的应用。在我的示例中，我创建了一个名为＆＃34; robviame://＆＃34;
在http://via.me/developers注册您的应用。这将为您提供客户端ID和客户端密码：

如果要对用户进行身份验证，请致电：

NSString *redirectUri = [[self redirectURI] stringByAddingPercentEscapesForURLParameterUsingEncoding:NSUTF8StringEncoding];
NSString *urlString = [NSString stringWithFormat:@"https://api.via.me/oauth/authorize/?client_id=%@&redirect_uri=%@&response_type=code", kClientID, redirectUri];
NSURL *url = [NSURL URLWithString:urlString];
[[UIApplication sharedApplication] openURL:url];

这样做会启动您的网络浏览器，并让用户有机会登录并授予您应用的权限。当用户完成该过程时，由于您已经定义了自定义网址方案，因此会在您的应用委托中调用以下方法：

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
    // do whatever you want here to parse the code provided back to the app
}

例如，我将为我的Via Me响应调用处理程序：

- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
    ViaMeManager *viaMeManager = [ViaMeManager sharedManager];

    if ([[url host] isEqualToString:viaMeManager.host])
    {
        [viaMeManager handleViaMeResponse:[self parseQueryString:[url query]]];

        return YES;
    }

    return NO;
}

// convert the query string into a dictionary

- (NSDictionary *)parseQueryString:(NSString *)query
{
    NSMutableDictionary *dictionary = [[NSMutableDictionary alloc] init];
    NSArray *queryParameters = [query componentsSeparatedByString:@"&"];

    for (NSString *queryParameter in queryParameters) {
        NSArray *elements = [queryParameter componentsSeparatedByString:@"="];
        NSString *key     = [elements[0] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
        NSString *value   = [elements[1] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
        value             = [[value componentsSeparatedByString:@"+"] componentsJoinedByString:@" "];

        [dictionary setObject:value forKey:key];
    }
    return dictionary;
}

例如，该处理程序可能会保存代码，然后请求访问令牌：

- (void)handleViaMeResponse:(NSDictionary *)parameters
{
    self.code = parameters[@"code"];

    if (self.code)
    {
        // save the code

        [[NSUserDefaults standardUserDefaults] setValue:self.code forKey:kViaMeUserDefaultKeyCode];
        [[NSUserDefaults standardUserDefaults] synchronize];

        // now let's authenticate the user and get an access key

        [self requestToken];
    }
    else
    {
        NSLog(@"%s: parameters = %@", __FUNCTION__, parameters);

        NSString *errorCode = parameters[@"error"];
        if ([errorCode isEqualToString:@"access_denied"])
        {
            [[[UIAlertView alloc] initWithTitle:nil
                                        message:@"Via Me functions will not be enabled because you did not authorize this app"
                                       delegate:nil
                              cancelButtonTitle:@"OK"
                              otherButtonTitles:nil] show];
        }
        else
        {
            [[[UIAlertView alloc] initWithTitle:nil
                                        message:@"Unknown Via Me authorization error"
                                       delegate:nil
                              cancelButtonTitle:@"OK"
                              otherButtonTitles:nil] show];
        }
    }
}

并且检索令牌的代码可能如下所示：

- (void)requestToken
{
    NSURL *url = [NSURL URLWithString:@"https://api.via.me/oauth/access_token"];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
    [request setHTTPMethod:@"POST"];

    NSDictionary *paramsDictionary = @{@"client_id"     : kClientID,
                                       @"client_secret" : kClientSecret,
                                       @"grant_type"    : @"authorization_code",
                                       @"redirect_uri"  : [self redirectURI],
                                       @"code"          : self.code,
                                       @"response_type" : @"token"
                                       };

    NSMutableArray *paramsArray = [NSMutableArray array];
    [paramsDictionary enumerateKeysAndObjectsUsingBlock:^(NSString *key, NSString *obj, BOOL *stop) {
        [paramsArray addObject:[NSString stringWithFormat:@"%@=%@", key, [obj stringByAddingPercentEscapesForURLParameterUsingEncoding:NSUTF8StringEncoding]]];
    }];

    NSData *paramsData = [[paramsArray componentsJoinedByString:@"&"] dataUsingEncoding:NSUTF8StringEncoding];
    [request setHTTPBody:paramsData];

    NSOperationQueue *queue = [[NSOperationQueue alloc] init];
    [NSURLConnection sendAsynchronousRequest:request queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
        if (error)
        {
            NSLog(@"%s: NSURLConnection error = %@", __FUNCTION__, error);
            return;
        }

        NSError *parseError;
        id results = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];

        if (parseError)
        {
            NSLog(@"%s: NSJSONSerialization error = %@", __FUNCTION__, parseError);
            return;
        }

        self.accessToken = results[@"access_token"];

        if (self.accessToken)
        {
            [[NSUserDefaults standardUserDefaults] setValue:self.accessToken forKey:kViaMeUserDefaultKeyAccessToken];
            [[NSUserDefaults standardUserDefaults] synchronize];
        }
    }];
}

希望这足以让你前进。这在http://via.me/developers页面中有更详细的描述。

我怎么能通过我社交网站集成到iPhone应用程序

1 个答案: