3D数组_unequal数字的字符串

Question

我意识到这可能以前已经完成，但是对于这种特殊的皱纹，搜索已经变为空白。

如果我们想要定义一个包含一些字符串的数组，我们可以这样做：

char *strings[] = {"one","two","three"};

如果我们想要定义一个字符串数组数组，我们可以这样做：

char *strings[][] =
{
  {"one","two","three"},
  {"first","second","third"},
  {"ten","twenty","thirty"}
};

但我似乎无法做到这一点：

char *strings[][] =
{
  {"one","two"},
  {"first","second","third","fourth","fifth"},
  {"ten","twenty","thirty"}
};

这样做会引发编译错误。

（来自string initialization in multidimensional array的例子）

Answer 1

来自here，

char *strings[][] 

strings是一个2D数组。

包括，

char *strings[][] =
{
  {"one","two","three"},
  {"first","second","third"},
  {"ten","twenty","thirty"}
};

编译器自动确定strings中的列数。在这种情况下，每个 strings[i]是2D数组中的一行。此外，它的类型为char (*string)[3]的指针（数组名称为指针），即为chare数组为sixe 3。

char *strings[][] =
{
  {"one","two"},
  {"first","second","third","fourth","fifth"},
  {"ten","twenty","thirty"}
};

在这种情况下，编译器无法创建数组（数组必须具有相同类型的元素），因为strings[0]的类型为char (*strings)[2]，strings[1]将是类型char (*strings)[5]和strings[2]类型为char (*strings)[3]

因此，编译器说incomplete element type。

您需要在声明时指定列数（N）（这将使char (*string)[N]类型的每一行）或动态分配。