如何在php中合并n个数组。我的意思是我怎样才能做到这样的工作:
array_merge(from : $result[0], to : $result[count($result)-1])
或
array_merge_recursive(from: $result[0], to : $result[count($result) -1])
其中$result
是一个包含多个数组的数组,如下所示:
$result = Array(
0 => array(),//associative array
1 => array(),//associative array
2 => array(),//associative array
3 => array()//associative array
)
我的结果是:
$result = Array(
0 => Array(
"name" => "Name",
"events" => 1,
"types" => 2
),
1 => Array(
"name" => "Name",
"events" => 1,
"types" => 3
),
2 => Array(
"name" => "Name",
"events" => 1,
"types" => 4
),
3 => Array(
"name" => "Name",
"events" => 2,
"types" => 2
),
4 => Array(
"name" => "Name",
"events" => 3,
"types" => 2
)
)
我需要的是
$result = Array(
"name" => "name",
"events" => array(1,2,3),
"types" => array(2,3,4)
)
答案 0 :(得分:151)
array_merge可以使用可变数量的参数,因此只需要一点call_user_func_array个诡计就可以将$result
数组传递给它:
$merged = call_user_func_array('array_merge', $result);
这基本上就像你输入的那样:
$merged = array_merge($result[0], $result[1], .... $result[n]);
现在使用5.6,我们有...
operator将数组解包到参数中,所以你可以:
$merged = array_merge(...$result);
并得到相同的结果。 *
*只要在解压缩数组中有整数键,结果相同,否则会出现E_RECOVERABLE_ERROR : type 4096 -- Cannot unpack array with string keys
错误。
答案 1 :(得分:3)
我非常喜欢complex857的答案,但它对我不起作用,因为我的数组中有数字键需要保留。
我使用+
运算符来保留键(如PHP array_merge with numerical keys中所述),并使用array_reduce
合并数组。
因此,如果要在保留数字键的同时合并数组中的数组,可以按如下方式进行:
<?php
$a = [
[0 => 'Test 1'],
[0 => 'Test 2', 2 => 'foo'],
[1 => 'Bar'],
];
print_r(array_reduce($a, function ($carry, $item) { return $carry + $item; }, []));
?>
结果:
Array
(
[0] => Test 1
[2] => foo
[1] => Bar
)
答案 2 :(得分:3)
如果您愿意:
您可以使用此功能:
function mergeArrayofArrays($array, $property = null)
{
return array_reduce(
(array) $array, // make sure this is an array too, or array_reduce is mad.
function($carry, $item) use ($property) {
$mergeOnProperty = (!$property) ?
$item :
(is_array($item) ? $item[$property] : $item->$property);
return is_array($mergeOnProperty)
? array_merge($carry, $mergeOnProperty)
: $carry;
}, array()); // start the carry with empty array
}
让我们看看它在行动..这里是一些数据:
简单结构:要合并的纯数组数组。
$peopleByTypesSimple = [
'teachers' => [
0 => (object) ['name' => 'Ms. Jo', 'hair_color' => 'brown'],
1 => (object) ['name' => 'Mr. Bob', 'hair_color' => 'red'],
],
'students' => [
0 => (object) ['name' => 'Joey', 'hair_color' => 'blonde'],
1 => (object) ['name' => 'Anna', 'hair_color' => 'Strawberry Blonde'],
],
'parents' => [
0 => (object) ['name' => 'Mr. Howard', 'hair_color' => 'black'],
1 => (object) ['name' => 'Ms. Wendle', 'hair_color' => 'Auburn'],
],
];
不太简单:数组数组,但希望指定人,忽略 计数。
$peopleByTypes = [
'teachers' => [
'count' => 2,
'people' => [
0 => (object) ['name' => 'Ms. Jo', 'hair_color' => 'brown'],
1 => (object) ['name' => 'Mr. Bob', 'hair_color' => 'red'],
]
],
'students' => [
'count' => 2,
'people' => [
0 => (object) ['name' => 'Joey', 'hair_color' => 'blonde'],
1 => (object) ['name' => 'Anna', 'hair_color' => 'Strawberry Blonde'],
]
],
'parents' => [
'count' => 2,
'people' => [
0 => (object) ['name' => 'Mr. Howard', 'hair_color' => 'black'],
1 => (object) ['name' => 'Ms. Wendle', 'hair_color' => 'Auburn'],
]
],
];
运行它
$peopleSimple = mergeArrayofArrays($peopleByTypesSimple);
$people = mergeArrayofArrays($peopleByTypes, 'people');
结果 - 两者都返回:
Array
(
[0] => stdClass Object
(
[name] => Ms. Jo
[hair_color] => brown
)
[1] => stdClass Object
(
[name] => Mr. Bob
[hair_color] => red
)
[2] => stdClass Object
(
[name] => Joey
[hair_color] => blonde
)
[3] => stdClass Object
(
[name] => Anna
[hair_color] => Strawberry Blonde
)
[4] => stdClass Object
(
[name] => Mr. Howard
[hair_color] => black
)
[5] => stdClass Object
(
[name] => Ms. Wendle
[hair_color] => Auburn
)
)
额外的乐趣: 如果要在数组或对象中单独输出一个属性,例如来自人物对象(或关联数组)的数组的“名称”,则可以使用此函数
function getSinglePropFromCollection($propName, $collection, $getter = true)
{
return (empty($collection)) ? [] : array_map(function($item) use ($propName) {
return is_array($item)
? $item[$propName]
: ($getter)
? $item->{'get' . ucwords($propName)}()
: $item->{$propName}
}, $collection);
}
getter用于可能受保护/私有的对象。
$namesOnly = getSinglePropFromCollection('name', $peopleResults, false);
返回
Array
(
[0] => Ms. Jo
[1] => Mr. Bob
[2] => Joey
[3] => Anna
[4] => Mr. Howard
[5] => Ms. Wendle
)
答案 3 :(得分:0)
试试这个
$result = array_merge($array1, $array2);
或者,您可以使用执行联合的+ op代替array_merge:
$array2 + array_fill_keys($array1, '');