我知道这有很多问题。我环顾四周,但我似乎没有犯错,我找到了答案。
我的锻炼资源的表单嵌套在用户之下,正在提供错误
undefined method `workouts_path' for #<#<Class:0x007f88939c9e60>:0x007f8891527b20>
表格如下:
= form_for @workout do |f|
... = f.submit
锻炼控制器新动作(产生错误的地方):
def new
@user = User.find(params[:user_id])
@workout = @user.workouts.new
end
锻炼模型以其独特的名字命名。控制器是复数。这是我的路线文件:
resources :users do
resources :workouts
end
相关的佣金路线输出:
user_workouts GET /users/:user_id/workouts(.:format) workouts#index
POST /users/:user_id/workouts(.:format) workouts#create
new_user_workout GET /users/:user_id/workouts/new(.:format) workouts#new
edit_user_workout GET /users/:user_id/workouts/:id/edit(.:format) workouts#edit
user_workout GET /users/:user_id/workouts/:id(.:format) workouts#show
PUT /users/:user_id/workouts/:id(.:format) workouts#update
DELETE /users/:user_id/workouts/:id(.:format) workouts#destroy
(也许它应该转到user_workouts_path,但我不知道为什么它不会自动执行。
另外,我正在使用mongo / mongoid,但我不知道为什么会有所作为。我让我的控制器放置@workout,它实例化了一个我可以在服务器日志中看到的新对象:
ActionView::Template::Error (undefined method `workouts_path' for #<#<Class:0x007f8893d0a480>:0x007f8893d12cc0>):
1: = form_for @workout do |f|
2:
3: = f.label :name, "Name (optional)"
4: = f.text_field :name
app/views/workouts/_form.html.haml:1:in `_app_views_workouts__form_html_haml___787289985246055156_70112286316300'
app/views/workouts/new.html.haml:3:in `_app_views_workouts_new_html_haml___1568138279872555052_70112285908620'
Rendered /Users/username/.rvm/gems/ruby-2.0.0-p195/gems/actionpack-3.2.11/lib/action_dispatch/middleware/templates/rescues/_trace.erb (2.5ms)
Rendered /Users/username/.rvm/gems/ruby-2.0.0-p195/gems/actionpack-3.2.11/lib/action_dispatch/middleware/templates/rescues/_request_and_response.erb (1.9ms)
Rendered /Users/username/.rvm/gems/ruby-2.0.0-p195/gems/actionpack-3.2.11/lib/action_dispatch/middleware/templates/rescues/template_error.erb within rescues/layout (12.4ms)
HERE GOES THE
#<Workout:0x007f8893da8ce8>
甚至测试过user_instance.workouts.new在控制台中工作,以确保它不是一些奇怪的mongo问题。
想法?
答案 0 :(得分:6)
由于锻炼路线嵌套在用户资源下,您需要form_for
的格式(IIRC):
form_for [@user, @workout] do |f|
答案 1 :(得分:0)
在我的情况下,我的问题是我的嵌套控制器( ExpansionController )具有单数名称,其父( EditionsController )具有复数名称。我已将嵌套控制器名称更改为复数( ExpansionsController ),其路由和工作正常。