在我的rails应用程序中,我有一种通过其API捕获ESPN标题的工作方法。但是,当我试图复制它以捕获所有NFL球员时,该方法失败了。
这是通过IRB工作的标题方法,当我在IRB中运行Headline.all时效果很好。
MODEL (headline.rb)
class Headline
include HTTParty
base_uri 'http://api.espn.com/v1/sports'
def self.all
response = Headline.get('/news/headlines',
:query => { :apikey => 'my_api_key' })
response["headlines"]
end
end
CONTROLLER (headlines_controller.rb)
class HeadlinesController < ApplicationController
def index
@headlines = Headline.all
end
end
这是NFL球员几乎相同的代码,它通过IRB返回“nil”。有什么想法吗?
MODEL (athlete.rb)
class Athlete
include HTTParty
base_uri 'http://api.espn.com/v1/sports'
def self.all
response = Athlete.get('/football/nfl/athletes',
:query => { :apikey => 'my_api_key_from_espn' })
response["athletes"]
end
end
CONTROLLER (athletes_controller.rb)
class AthletesController < ApplicationController
def index
@athletes = Athlete.all
end
end
更新:我应该评论我可以通过浏览器成功运行GET请求(并查看结果)来自...... http://api.espn.com/v1/sports/football/nfl/athletes/?apikey=my_api_key_from_espn
感谢。这是我向StackOverflow发表的第一篇文章,以便对我的问题的方法/格式提供反馈。
答案 0 :(得分:0)
我得到了它的工作,这是我修改的Athlete.all方法语法。基本上,运动员API响应阵列需要比标题api更深一些地走路。
class Athlete
include HTTParty
base_uri 'http://api.espn.com/v1/sports'
def self.all
response = Athlete.get('/football/nfl/athletes',
:query => { :apikey => 'my_api_key_from_espn' })
response['sports'].first['leagues'].first['athletes']
end
end
为了更好的衡量,这是我的app / views / athletes / index.html.erb语法:
<ul id="athletes">
<% @athletes.each do |item| %>
<li class="item"><%= link_to item["displayName"], item["links"]["web"]["athletes"]["href"] %></li>
<% end %>
</ul>
(特别感谢@ivanoats,当然还有@deefour。)