Python .remove（）方法删除列表中的意外项

Question

我写了这个剧本：

soilMod = ['ptaaco']
n = 2

soilModSplit = [soilMod[i:i+n] for i in range(0, len(soilMod), n)] # This returns ['pt', 'aa', 'co']

alphaTest = soilModSplit # I want to maintain the original list built before I remove items below. This returns ['pt', 'aa', 'co'] as well

if 'pt' in soilModSplit:
      soilModSplit.remove('pt')
      print soilModList # This returns ['aa', 'co']
      print alphaTest # This also returns ['aa', 'co'] It's missing the original ['pt', 'aa', 'co'] and I didn't ask the script to remove it from this particular list.

出于某种原因，当我从soilModSplit中删除项目（'pt'）时，它也会从alphaTest中删除该项目。这是预期的结果吗？似乎构建在soilModSplit上的任何变量（在这种情况下，alphaTest）都依赖于对soilModSplit采取的任何操作。也许我做错了什么？有办法解决这个问题吗？

谢谢， 麦克

Answer 1

alphaTest = soilModSplit 

alphatest只是绑定到soilModSplit的同一列表的另一个名称。制作浅色副本：

alphaTest = list(soilModSplit )

Answer 2

执行alphaTest = soilModSplit时，您没有创建副本。您只有两个引用相同列表的名称。如果要保存副本，请执行alphaTest = list(soilModSplit)。