用户控制器

创建用户功能

$newUser = new User;

if($userData['organization'])
    $newUser->organization = self::_professional('Organization', $newUser, $userData);
else
    $newUser->school = self::_professional('School', $newUser ,$userData);

创建或检索学校/组织ID

private function _professional($type, $newUser, $userData)
{
    if ( $orgId = $type::where('name', '=', $userData[strtolower($type)])->only('id'))
        return $orgId;
    else
    {
        try {
            $org = $type::create(array('name' => $userData[strtolower($type)]));
            return $org->attributes['id'];
        } catch( Exception $e ) {
            dd($e);
        }
    }
}

模型

用户模型

class User extends Eloquent {

    public function organization()
    {
        return $this->belongs_to('Organization');
    }

    public function school()
    {
            return $this->belongs_to('School');
    }
}

组织/学校模式

class Organization extends Eloquent {

    public function user() 
    {
        return $this->has_many('User');
    }

}

迁移

用户迁移

....
$table->integer('organization_id')->unsigned()->nullable();
$table->foreign('organization_id')->references('id')->on('organizations');

$table->integer('school_id')->unsigned()->nullable();
$table->foreign('school_id')->references('id')->on('schools');
....

组织/学校迁移

....
$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
....

现在，我的问题是：

有没有更好的方法来生成用户 - ＆gt;学校/组织关系，那么上面使用的那个？如果是这样，怎么样？
通过以下方式检索用户的学校/组织名称的更好方法：School::find($schoolId)->get()

执行User::find(1)->school()不会仅检索school的任何数据：

[base:protected] => User Object
(
    [attributes] => Array
        (
            [id] => 1
            [nickname] => w0rldart
            ....
            [organization_id] => 
            [school_id] => 1
            ...
        )
    [relationships] => Array
        (
        )

    [exists] => 1
    [includes] => Array
        (
        )

)

[model] => School Object
(
    [attributes] => Array
        (
        )

    [original] => Array
        (
        )

    [relationships] => Array
        (
        )

    [exists] => 
    [includes] => Array
        (
        )

)

Answer 1

// You have to save this before you can tied the organizations to it
$new_user->save();

// The organizations that you want to tie to your user
$oganization_ids = array(1, 2, 3);

// Save the organizations
$result = $new_user->organization()->sync($oganization_ids);

Answer 2

有没有更好的方法来生成User -> School/Organization关系，然后是上面使用的关系？如果是这样，怎么样？

Eloquent应该能够自动处理，请参见此处：http://three.laravel.com/docs/database/eloquent#inserting-related-models。

检索用户的学校/组织名称的更好方法是：School::find($schoolId)->get()

如果您的意思是无法检索关系信息：has_name和belongs_to返回一个Elloquent Expression，您仍然需要在它们上面调用get()来检索对象或集合你想要的。

我应对此问题的方法是为关系添加一个参数，以确定该方法是否应返回表达式或结果：

$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
$table->unique('name');

...

class User extends Eloquent
{
    /**
     * Return an Elloquent Expression or a collection (or object)
     * Defaults to return a collection
     */
    public function organization ($as_expression=FALSE) {
        $related = $this->belongs_to('Organization');
        return $as_expression ? $related : $related->get();
    }

    public function school ($as_expression=FALSE) {
        $related = $this->belongs_to('School');
        return $as_expression ? $related : $related->get();
    }

    ...

    public function create ($user_data=array()) {
        $newUser = new User;
        $activity = @$user_data['organization'] ?
            'organization' : (@$user_data['school'] ? 'school' : '');

        switch ($activity) {
            case 'organization':
            case 'school':
                /**
                 * Call the corresponding method, return as Eloquent Expression
                 * Use a string to be verbose, TRUE does fine if wanted
                 */
                $new_user->{$activity}('as_expression')->save(array( 'name' => $user_data[$activity]));

                break;
            default:
                break;
        }

        return $new_user;
    }
}

...

class Organization extends Eloquent
{
    public function user ($as_expression=FALSE) {
        $related = $this->has_many('User');
        return $as_expression ? $related : $related->get();
    }
}

Laravel插入和检索关系

用户控制器

模型

迁移

2 个答案: