Question

我正在尝试根据手册中的安全示例在symfony2中实现登录，但似乎有些错误，它没有显示任何错误或任何消息。这是控制器：

  <?php

namespace WN\Bundle\UsersBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\Security\Core\SecurityContext;
use WN\Bundle\UsersBundle\Entity\User;
use WN\Bundle\UsersBundle\Entity\UsersRepository;

class SecurityController extends Controller {

    public function loginAction() {

        $request = $this->getRequest();
        $session = $request->getSession();

        if($request->attributes->has(SecurityContext::AUTHENTICATION_ERROR))
        {
            $error = $request->attributes->get(SecurityContext::AUTHENTICATION_ERROR);

        }
        else
        {
            $error = $session->get(SecurityContext::AUTHENTICATION_ERROR);
            $session->remove(SecurityContext::AUTHENTICATION_ERROR);
        }
        return $this->render('WNUsersBundle:Security:login.html.twig',
                array('last_username' => $session->get(SecurityContext::LAST_USERNAME),
                        'error' => $error
                        ));
    }

}

?>

更新

这是bundle / config / routing.yml

wn_home:
    pattern:  /secured
    defaults: { _controller: WNHomeBundle:Home:index }
wn_users_homepage:
    pattern:  /hello/{name}
    defaults: { _controller: WNUsersBundle:Default:index }
wn_users_register:
    pattern:  /register
    defaults: { _controller: WNUsersBundle:Register:register }
wn_users_login:
    pattern:  /login
    defaults: { _controller: WNUsersBundle:Security:login }
login_check:
    pattern:   /login_check

这是security.yml

jms_security_extra:
    secure_all_services: false
    expressions: true

security:
    encoders:
        Symfony\Component\Security\Core\User\User: plaintext
        WN\Bundle\UsersBundle\Entity\User: sha256
    role_hierarchy:
        ROLE_ADMIN:       ROLE_USER
        ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]

    providers:
         users:
            entity: { class: WNUsersBundle:User }   

    firewalls:
        login:
            pattern:  ^/login
            security: false
        secured_area:
            pattern:    ^/secured
            form_login:
                check_path: /login_check
                login_path: /login
            logout:
                path:   /logout
                target: /login
            #anonymous: ~
            #http_basic:
            #    realm: "Secured Demo Area"

    access_control:
        #- { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY, requires_channel: https }
         - { path: ^/login$, roles: IS_AUTHENTICATED_ANONYMOUSLY }
         - { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY }

这是login.html.twig

  {% extends '::base.html.twig' %}
    {% block content %}
    {% if error %}
    <div>{{ error.message }}</div>
    {% endif %}
    <form action="{{ path('login_check') }}" method="post">

    <label for="Username">Username</label>
    <input type="text" name="_username" id="username" value="{{ last_username }}">

    <label for="Password">Password</label>
    <input type="password" name="_password" id="password">
    <br />

    <input  type="submit" name="submit" value="Login">
    </form>

{% endblock %}

现在我得到的错误是：无法找到路径“/ login_check”的控制器。也许您忘了在路由配置中添加匹配的路由？

有谁知道如何解决这个问题？

Answer 1

您必须在登录控制器中定义其他两个公共功能。你没有在其中放置任何东西，它们只是Symfony2安全控制器机制工作的基础。

/**
 * @Route("/login_check", name="login_check")
 */
public function loginCheckAction()
{
}

/**
 * @Route("/logout", name="logout")
 */
public function logoutAction()
{
}

希望这可以帮助你。

symfony2登录基于手册

1 个答案: