我的java程序上有日期列表。我想制作一个方法来返回我在参数中传递的天数。
示例:我将字符串“Tue”传递给此方法。然后这个方法返回int 20.假设int 20是星期二作为日期名称的日期计数。
抱歉我的英文。因为它不是我的自然语言
答案 0 :(得分:1)
您可以将日期转换为日历实例:
int groupByDays(List<Date> dateList, int dayToMatch) { //dayToMatch can be defined as Calendar.TUESDAY or Calendar.MONDAY ...
int counter = 0;
for (Date date : dateList) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
int day = cal.get(Calendar.DAY_OF_WEEK);
if (day == dayToMatch)
counter++;
System.out.println("Day is : "+day); //This will return the day index compare with actual value to get the DAY in string format
}
return counter;
}
相当于Day的指数(直接从java.util.Calendar中选取):
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Sunday.
*/
public final static int SUNDAY = 1;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Monday.
*/
public final static int MONDAY = 2;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Tuesday.
*/
public final static int TUESDAY = 3;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Wednesday.
*/
public final static int WEDNESDAY = 4;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Thursday.
*/
public final static int THURSDAY = 5;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Friday.
*/
public final static int FRIDAY = 6;
/**
* Value of the {@link #DAY_OF_WEEK} field indicating
* Saturday.
*/
public final static int SATURDAY = 7;
使用这些信息,您可以对细节进行分组。
答案 1 :(得分:0)
这应该这样做:
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
ArrayList<Date> dates = new ArrayList<Date>();
dates.add(sdf.parse("11/06/2013"));//Tuesday
dates.add(sdf.parse("15/06/2013"));//Saturday
dates.add(sdf.parse("17/06/2013"));//Monday
dates.add(sdf.parse("18/06/2013"));//Tuesday
dates.add(sdf.parse("22/06/2013"));//Saturday
dates.add(sdf.parse("25/06/2013"));//Tuesday
System.out.println(checkDay(dates , "Mon"));
System.out.println(checkDay(dates , "Tue"));
System.out.println(checkDay(dates , "Wed"));
System.out.println(checkDay(dates , "Sat"));
public int checkDay(ArrayList<Date> list, String day)
{
int count = 0;
SimpleDateFormat sdf = new SimpleDateFormat("EE");
for(Date d : list)
{
if(sdf.format(d).equals(day))
count++;
}
return count;
}
看到它在这里工作:
如果你计划多次这样做,你最好运行一次并将计数存储在一个hashmap中:
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
ArrayList<Date> dates = new ArrayList<Date>();
dates.add(sdf.parse("11/06/2013"));//Tuesday
dates.add(sdf.parse("15/06/2013"));//Saturday
dates.add(sdf.parse("17/06/2013"));//Monday
dates.add(sdf.parse("18/06/2013"));//Tuesday
dates.add(sdf.parse("22/06/2013"));//Saturday
dates.add(sdf.parse("25/06/2013"));//Tuesday
HashMap counts = getCounts(dates);
System.out.println(counts.get("Mon"));
System.out.println(counts.get("Tue"));
public static HashMap getCounts(ArrayList<Date> list)
{
HashMap counts = new HashMap();
SimpleDateFormat sdf = new SimpleDateFormat("EE");
for(Date d : list)
{
String form = sdf.format(d);
if(counts.containsKey(form))
counts.put(form,((int)counts.get(form))+1);
else
counts.put(form,1);
}
return counts;
}
在此处查看: