如何翻译为Linq Expression

时间:2013-06-10 06:13:39

标签: sql linq lambda sql-to-linq-conversion

我有以下sql命令,我无法将其转换为linq

select Distinct(fp.Parks_Id)
from ParkFeaturePark fp
Inner Join Parkfeatures feat on fp.ParkFeatures_Id = feat.Id
Inner Join Parks p On fp.Parks_Id = p.Id
where  p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =1 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =2 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =31     )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =42 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =106 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =118 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =4 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =6 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =10 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =18 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =22 )
    And p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =46 )

这里的扭曲是......我必须使用用户选择的组合..样本

    p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =1 )
    AND p.Id In (Select Parks_Id from ParkFeaturePark where ParkFeatures_Id =4 )

或用户选择任何其他组合..

感谢您的回复

2 个答案:

答案 0 :(得分:2)

这不是答案,而是好的风格编码 -

SELECT DISTINCT(fp.Parks_Id)
FROM dbo.ParkFeaturePark fp
JOIN dbo.Parkfeatures feat ON fp.ParkFeatures_Id = feat.Id
JOIN dbo.Parks p ON fp.Parks_Id = p.Id
WHERE p.Id IN (
        SELECT Parks_Id 
        FROM dbo.ParkFeaturePark 
        WHERE ParkFeatures_Id IN (1, 2, 31, 42, 106, 118, 4, 6, 10, 18, 22, 46)
    )

答案 1 :(得分:2)

假设您有导航属性Park.ParkFeatureParksParkFeaturePark.Parkfeatures。 (否则将能够创建它们)。然后你可以这样做:

int[] featureIds = new { 1, 2, 31, 42, 106, 118, .. };

var query = from p in context.Parks
            where p.ParkFeatureParks
                   .SelectMany(pfp => pfp.Parkfeatures)
                   .All(feature => featureIds
                                   .Contains(id => feature.ParkFeatures_Id))
            select p.Parks_Id;