Question

我有一个表单，用户根据状态和城市选择框或文本框选择国家/地区。

在国家/地区，如果选择了INDIA，那么它应该使用州和城市选择填充选择框，否则填写要写入的城市和州的文本框。我能够实现它，但它有两个问题 -

第一个是当用户选择国家/地区时，隐藏部分有空间
第二种表单仅针对不适用于INDIA的其他国家/地区提交

脚本和HTML中可能存在什么问题？下面是代码 -

<script type="text/javascript">
    function loadbox()
    {
    //var cnty=document.getElementById('country').slected;
    var x=document.getElementById("country1").selectedIndex;
    var y=document.getElementsByTagName("option")[x].value;
    if(y==22)
    {
    document.getElementById("selectbox").style.visibility = "visible";
    document.getElementById("textbox4cnty").style.visibility = "hidden";
    }
    else {
    document.getElementById("selectbox").style.visibility = "hidden";
    document.getElementById("textbox4cnty").style.visibility = "visible";
    }
    }
    </script>

html部分

    <label for="country">COUNTRY</label>
<select id="country1" name="country1" onChange="loadbox()">         
<option value="" selected="selected" />SELECT</option>
<?php
$sql="SELECT * FROM  `country` ";
$result = mysql_query($sql);
while($row=mysql_fetch_array($result))
{
 ?>
<option value="<?php echo $row['country_id']; ?>">
<?php echo $row['country_name']; ?></option>
<?php                                            
  }
 ?>                                  
<option value="others">Others</option>
</select>         
<div id="selectbox" style="visibility:hidden">
<label for="State">STATE </label>
<select id="state1" name="state1"
onchange="getCity('select_city.php?state_id='+this.value)">
<option value="">SELECT</option>
<?php
$sql1="SELECT * FROM  `state`  ";
$result1 = mysql_query($sql1);
 while($row1=mysql_fetch_array($result1))
{
?>
<option value="<?php echo $row1['state_id']; ?>">
<?php echo $row1['state_name']; ?></option>
<?php
}
?>
</select>
<label for="STREET">CITY </label>
<select id="city1" name="city1">
<option value="">select</option>
 </select> <br/>
<div>
<div id="textbox4cnty" style="visibility:hidden">
<label for="State">STATE </label>
<input type="text" placeholder="STATE" name="state1" required><br />
<label for="STREET">CITY </label>
<input type="text" placeholder="CITY" name="city1" required><br />
</div>

Answer 1

更改

if(y==22) { document.getElementById("selectbox").style.visibility = "visible"; document.getElementById("textbox4cnty").style.visibility = "hidden"; } else { document.getElementById("selectbox").style.visibility = "hidden"; document.getElementById("textbox4cnty").style.visibility = "visible"; }

以

if(y==22) { document.getElementById("selectbox").style.visibility = "visible"; document.getElementById("textbox4cnty").style.visibility = "hidden"; document.getElementById("selectbox").disabled=false; document.getElementById("textbox4cnty").disabled=true; } else { document.getElementById("selectbox").style.visibility = "hidden"; document.getElementById("textbox4cnty").style.visibility = "visible"; document.getElementById("selectbox").disabled=true; document.getElementById("textbox4cnty").disabled=false; }

Answer 2

您的代码存在问题。您可以使用页面上所有选项的通用选择

以下是我如何在不深入挖掘并保持内联事件处理程序的情况下编写代码。它应该是不引人注目的，但一次只有一件事

function loadbox(sel)     {
  var isIndia=sel.options[sel.selectedindex].text==="INDIA";
  document.getElementById("selectbox").style.display = (isIndia)?"":"none";
  document.getElementById("textbox4cnty").style.display = (isIndia)?"none":"";
  // and because you do not have ID on the second field names state1
  document.getElementsByName("state1")[0].disabled=!isIndia; 
  document.getElementsByName("state1")[1].disabled=isIndia;
  document.getElementsByName("city1")[0].disabled=isIndia;
}

使用

<select id="country1" name="country1" onChange="loadbox(this)">

和

<div id="selectbox" style="display:none">

和

<div id="textbox4cnty" style="display:none">

删除隐藏元素和表单提交之间的空格

2 个答案: