Question

有一次与这一次....我有以下简化表

+---------+   +-------------+   +-------------+
| fields  |   | details     |   | customers   |
+---------+   +-------------+   +-------------+
| id      |   | customer_ID |   | customer_ID |
| caption |   | field_id    |   | progress    |
+---------+   | field_value |   +-------------+
              +-------------+

字段表有多个“字段”，例如first_name，last_name等，它们上面有id，然后详细信息中包含相应的值，Customers表处理“主”客户信息。

我要做的是获取details.field_value，fields.caption WHERE details.customer_id = customers_id AND customers.progress = X然后用last_name的id对它进行ORDER。

我为了让这个工作变得疯狂，所以我想在这里问一下午餐。

谢谢大家的帮助！

Answer 1

我认为您可以使用INNER JOIN查询

来实现此目的

SELECT c.id, c.caption
FROM customers a
INNER JOIN details b
ON a.customers_ID = b.customers_ID
INNER JOIN fields c
ON b.field_id = c.id
WHERE a.progress = ?
ORDER BY b.last_name ASC

Answer 2

试试这个：

SELECT d.field_value, f.caption
FROM (details d INNER JOIN fields f ON d.field_id = f.id)
INNER JOIN customers c ON d.customer_ID = c.customer_ID
WHERE c.progress = 'X'
ORDER BY f.id

Answer 3

一种方式：

select c.customer_ID,
       group_concat(concat(f.caption,':',d.field_value)) Data_Fields,
       max(case f.caption when 'last_name' then d.field_value end) last_name
from customers c
join details d on c.customer_ID = d.c.customer_ID
join fields f on d.field_id = f.id
where c.progress=?
group by c.customer_ID
order by last_name

从多个表中选择MySQL记录并进行排序

3 个答案: