MySql使用同一个表中的两个不同的数据进行两次计数

Question

表1

"id"    "name"      "description"   "path"                              "country"   "status"
"1"     "Title 1"   "Description 1" "US > Consumer > Home Applicances"  "US"        "0"
"2"     "Title 2"   "Description 2" "US > Business > Legal Charges"     "UK"        "0"

我正尝试在同一张桌子中使用不同counts的两个wheres。

我在这里遇到了其他问题，但没有人喜欢我这样做的方式。

我目前正在使用两个sqls和更多代码：

select count(id) from table where id = 1 and select count(id) from table where id = 2

如果两者都在那里，我将继续我的其余部分。我怎样才能在MySql中做这样的事情？

Answer 1

您可以使用子选择。

SELECT * FROM 
  (SELECT COUNT(id) AS count_one FROM table WHERE id = 1) a,
  (SELECT COUNT(id) AS count_two FROM table WHERE id = 2) b

Answer 2

这可能对你有帮助 -

    $query = "SELECT SUM(Case when id=1 then 1 else 0 end) as count_one,
SUM(Case when id=2 then 1 else 0 end) as count_two FROM table";