Question

我已将jqgrid实现为。，

$(function () {
    $("#accountHeadList").jqGrid({
        //url: '../../jqGridHandler1.ashx',
        url: '/Personalize/GetAccountHeads',
        datatype: 'json',
        width  : 400,
        height : 300, 
        colNames: ['name', 'value'],
        colModel: [
                { name: 'name', width: 100, sortable: true },
                { name: 'value', width: 100, sortable: true },
        ],
        rowNum: 10,
        rowList: [10, 20, 30],
        pager: '#gridPager',
        viewrecords: true,
        sortorder: 'asc',
        multiselect: true,
        caption: 'Account Heads',         
    });

    $("#accountHeadList").jqGrid('navGrid', '#gridPager', { edit: false, add: false, del: false });
});

当我将JSON返回为。时，

{"rows":[{"id":0,"cell":["Accounts Receivable",""]},{"id":1,"cell":["Acd",""]},{"id":2,"cell":["Bank Accounts",""]},{"id":3,"cell":["Cash On Hand",""]},{"id":4,"cell":["Income Tax Payable",""]},{"id":5,"cell":["Interest Payable",""]},{"id":6,"cell":["Investment Premium Payable",""]},{"id":7,"cell":["Prepaid Expenses",""]},{"id":8,"cell":["Salary \u0026 Wage Payable",""]},{"id":9,"cell":["Salary Receivable",""]},{"id":10,"cell":["Short Term Borrowing",""]}],"page":1,"total":1,"records":10}

解析得很好而且我在网格中获取数据。如果。，如果我传递数据如下。，它无法加载数据，只是空的表格列出现在网格中，（但同一个没有行）。

{"rows":[{"id":0,"cell":{"name":"Accounts Receivable","value":null}},{"id":1,"cell":{"name":"Acd","value":null}},{"id":2,"cell":{"name":"Bank Accounts","value":null}},{"id":3,"cell":{"name":"Cash On Hand","value":null}},{"id":4,"cell":{"name":"Income Tax Payable","value":null}},{"id":5,"cell":{"name":"Interest Payable","value":null}},{"id":6,"cell":{"name":"Investment Premium Payable","value":null}},{"id":7,"cell":{"name":"Prepaid Expenses","value":null}},{"id":8,"cell":{"name":"Salary \u0026 Wage Payable","value":null}},{"id":9,"cell":{"name":"Salary Receivable","value":null}},{"id":10,"cell":{"name":"Short Term Borrowing","value":null}}],"page":1,"total":1,"records":10}

我可以看到{}中[]和cell的区别，这可能是错误的根源。但为什么会这样呢？

Answer 1

服务器应该以jqGrid期望数据的默认格式返回数据，或者您应该使用jsonReader通知jqGrid有关数据格式的信息。

在the feature request和the pull request中已经是jqGrid的一部分。因此，如果您使用当前版本的jqGrid，那么jqGrid仍然可以读取许多（但不是全部）错误的格式化的输入数据。无论如何，了解使用哪个版本的jqGrid 非常重要。

如果您更喜欢在服务器的JSON响应中使用对象形式的数据，那么服务器应该以

的形式返回rows部分答案

"rows":[
    {"id":0,"name":"Accounts Receivable","value":null},
    {"id":1,"name":"Acd","value":null},
    {"id":2,"name":"Bank Accounts","value":null},
    ...
 ]

（"cell"属性应删除）。如果使用不支持自动检测JSON输入数据的旧版jqGrid，则必须另外添加jsonReader: {repeatitems: false}。

通过jqGrid解析JSON：{}和[]之间的差异

1 个答案: