Question

我正在使用insert into select将一行从table1复制到table2，除了我需要从同一个表中的两个不同的行中选择数据。怎么办呢？

表1

"id"    "name"      "description"   "path"                              "country"   "status"
"1"     "Title 1"   "Description 1" "US > Consumer > Home Applicances"  "US"        "0"
"2"     "Title 2"   "Description 2" "US > Business > Legal Charges"     "UK"        "0"

表2

"id"    "name"  "description"   "path"  "newId" "newPath"   "country"   "status"

当前的Sql

insert into table2 select null, name, description, path, country, status from table1 where id=1;

尝试一气呵成

$currentId = 1;
$newId = 2;

// This'll update columns name, description, path, country, status
insert into table2 select null, name, description, path, country, status from table1 where id=$currentId;

// This'll need to update newId, newPath same row
insert into table2 newId, newPath from table1 where id=$newId;

//Trying to achiev    
insert into table2 select null, name, description, path, country, status from table1 where id=$currentId, insert into table2 //newId, newPath  select id, path from table1 where id=$newId;

Answer 1

使用JOIN

INSERT INTO table2
SELECT t1.id, t1.name, t1.description, t1.path, t2.id, t2.path, t1.country, t1.status
  FROM table1 t1 JOIN table1 t2
    ON t1.id = $currentId AND t2.id = $newId

这是 SQLFiddle 演示

从同一个表中插入两个选项

1 个答案: