我正在尝试更多地了解线程,并认为提出解决生产者/消费者问题的解决方案将是一个良好的开端。我对解决方案的一个限制是,消费者并不提前知道生产者生产了多少。代码按预期运行,我运行了很多次,但这并不意味着它没有缺陷。这个解决方案有问题吗?
package Multithreading.ProducerConsumer;
import java.util.LinkedList;
import java.util.concurrent.Semaphore;
public class ProducerConsumer
{
private class Producer implements Runnable
{
@Override
public void run()
{
for(int i = 0; i < 1000; i++)
{
try
{
canProduce.acquire();
mutex.acquire();
queue.add(i);
mutex.release();
canConsume.release();
}
catch (InterruptedException ex)
{
;
}
}
try
{
canConsume.acquire();
isTryingToFinish = true;
canConsume.release();
}
catch (InterruptedException ex)
{
;
}
}
}
private class Consumer implements Runnable
{
@Override
public void run()
{
while(!isDone)
{
try
{
canConsume.acquire();
mutex.acquire();
System.out.println(queue.pop());
if(isTryingToFinish && queue.isEmpty())
{
isDone = true;
}
mutex.release();
canProduce.release();
}
catch (InterruptedException ex)
{
;
}
}
}
}
Semaphore canProduce;
Semaphore canConsume;
Semaphore mutex;
boolean isTryingToFinish = false;
boolean isDone = false;
final static int bufferSize = 100;
LinkedList<Integer> queue;
public ProducerConsumer()
{
queue = new LinkedList<>();
canProduce = new Semaphore(bufferSize);
canConsume = new Semaphore(0);
mutex = new Semaphore(1);
}
public void Go() throws InterruptedException
{
Thread p = new Thread(new Producer());
Thread c = new Thread(new Consumer());
p.start();
c.start();
p.join();
c.join();
System.out.println("Job Complete!");
}
public static void main(String[] args) throws InterruptedException
{
ProducerConsumer p = new ProducerConsumer();
p.Go();
}
}
答案 0 :(得分:0)
您可以查看MSDN's 'Example 2: Synchronizing two threads: a producer and a consumer'。这是c#,但这应该不是问题。