Question

它在regexr中工作正常。如果我将它插入到我的preg_match（）中：

$reason = preg_match('/(?<=error\: )(.*?)(?=\; Request)/', $message);

它总是返回0.

我认为它与preg_match（）期望格式化模式的方式有关吗？

Answer 1

请尝试使用此正则表达式，因为您已经使用过＆＃39;？＆＃39;切换贪婪：

$reason = preg_match('/(?<=error\: )(.*)(?=\; Request)/', $message);`

Answer 2

对我来说似乎没问题。检查$ message是否未以任何方式转义或与该regexr不同。

$message = 'Request have return error: Invalid email syntax; Request: {"jsonrpc":"2.0","method":"add_contact","params":["420a42ea1685c9a273f26378aa82081b",{"campaign":"nfzM","name":"Chris Allen","email":"eric","ip":"127.0.0.1","customs":[{"name":"phone","content":"123456"},{"name":"address","content":"123 Fake Street"},{"name":"city","content":"Chicago"},{"name":"state","content":"IL"},{"name":"zipcode","content":"0001"},{"name":"country","content":"United States"},{"name":"company_name","content":"Acme"},{"name":"store_url","content":"http:\/\/www.google.com"},{"name":"timestamp","content":"06.10.13"},{"name":"subscriber_ip","content":"127.0.0.1"}]}],"id":2};';

$reason = preg_match('/(?<=error\: )(.*?)(?=\; Request)/', $message);

var_dump($reason);

回馈：

int(1)

Answer 3

我认为您的问题不在您的正则表达式中，请注意;和:不需要转义。不过我建议你用这个：

if (preg_match('~error: \K[^;]++(?=; Request)~', $message, $reason))
    print_r($reason);

注意 $ reason

的位置

为什么这种模式在preg_match（）中不起作用？

3 个答案: